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#define CUBE(I) (I * I * I) int c = 81 / CUBE0CUBE(2 + 1); |
As a result, the invocation
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int c = 81 / CUBE0CUBE(2 + 1); |
expands to
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int a = 81 / (2 + 1 * 2 + 1 * 2 + 1); /* evalutaes to 11 */ |
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Code Block |
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#define CUBE(I) (I * I * I) int c = 81 / CUBE0CUBE(2 + 1); |
As a result, the invocation
Code Block |
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int c = 81 / CUBE0CUBE(2 + 1); |
expands to
Code Block |
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int a = 81 / (2 + 1 * 2 + 1 * 2 + 1); /* evalutaes to 11 */ |
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