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Code Block
#define CUBE(I) (I * I * I)
int c = 81 / CUBE0CUBE(2 + 1);

As a result, the invocation

Code Block
int c = 81 / CUBE0CUBE(2 + 1);

expands to

Code Block
int a = 81 / (2 + 1 * 2 + 1 * 2 + 1);  /* evalutaes to 11 */

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