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Calling the signal() function in a multithreaded program is undefined behavior (see undefined behavior 135).

Noncompliant Code Example

This noncompliant code example invokes the signal() function from a multithreaded program.:

Code Block
bgColor#ffcccc
langc
#include <signal.h>
#include <threads.h>
 
volatile sig_atomic_t flag = 0;

void handler(int signum) {
  flag = 1;
}

/* Runs until user sends SIGUSR1 */
int func(void *data) {
  while (!flag) {
    /* ... */
  }
  return 0;
}

int main(void) {
  signal(SIGUSR1, handler); /* Undefined! */
  thrd_t tid;
  
  if (thrd_success != thrd_create(&tid, func, NULL)) {
    /* Handle error */
  }

  /* ... */

  return 0;
}

NOTE: The SIGUSR1 signal value is not defined in the C Standard; consequently, this is not a C-compliant code example.

Compliant Solution

This compliant solution uses an object of type atomic_flag to indicate when the child thread should terminate its loop.:

Code Block
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langc
#include <stdatomic.h>
#include <threads.h>
 
atomic_flag flag = ATOMIC_VAR_INIT(0);

int func(void *data) {
  while (!flag) {
    /* ... */
  }
  return 0;
}

int main(void) {
  int result;
  thrd_t tid;
  
  if (thrd_success != thrd_create(&tid, func, NULL)) {
    /* Handle error */
  }

  /* ... */

  /* Set flag when done */
  while (!atomic_flag_test_and_set(&flag))
    ; /* Continue attempts */

  return 0;
}

Exceptions

CON37-EX1: Platforms Implementations such as POSIX that provide defined behavior when multithreaded programs use custom signal handlers are exempt from this rule . For example, this exception is specified by POSIX Section XSH 2.9.1 Thread-Safety [IEEE Std 1003.1-2013].

Risk Assessment

Mixing signals and threads causes undefined behavior.

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Search for vulnerabilities resulting from the violation of this rule on the CERT website.

Bibliography

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