Calling the signal()
function in a multithreaded program is undefined behavior (see undefined behavior 135).
Noncompliant Code Example
This noncompliant code example invokes the signal()
function from a multithreaded program.:
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#include <signal.h> #include <threads.h> volatile sig_atomic_t flag = 0; void handler(int signum) { flag = 1; } /* Runs until user sends SIGUSR1 */ int func(void *data) { while (!flag) { /* ... */ } return 0; } int main(void) { signal(SIGUSR1, handler); /* Undefined! */ thrd_t tid; if (thrd_success != thrd_create(&tid, func, NULL)) { /* Handle error */ } /* ... */ return 0; } |
NOTE: The SIGUSR1
signal value is not defined in the C Standard; consequently, this is not a C-compliant code example.
Compliant Solution
This compliant solution uses an object of type atomic_flag
to indicate when the child thread should terminate its loop.:
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#include <stdatomic.h> #include <threads.h> atomic_flag flag = ATOMIC_VAR_INIT(0); int func(void *data) { while (!flag) { /* ... */ } return 0; } int main(void) { int result; thrd_t tid; if (thrd_success != thrd_create(&tid, func, NULL)) { /* Handle error */ } /* ... */ /* Set flag when done */ while (!atomic_flag_test_and_set(&flag)) ; /* Continue attempts */ return 0; } |
Exceptions
CON37-EX1: Platforms Implementations such as POSIX that provide defined behavior when multithreaded programs use custom signal handlers are exempt from this rule . For example, this exception is specified by POSIX Section XSH 2.9.1 Thread-Safety [IEEE Std 1003.1-2013].
Risk Assessment
Mixing signals and threads causes undefined behavior.
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Search for vulnerabilities resulting from the violation of this rule on the CERT website.
Bibliography
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