While it has been common practice to use integers and pointers interchangeably in C, pointer-to-integer and integer-to-pointer conversions are implementation-defined.
The only value that can be considered interchangeable between pointers and integers is the constant 0. Except in this case, conversions between integers Conversions between integers and pointers can have undesired consequences depending on the implementation. According to the C standard, Section 6.3.2.3 [ISO/IEC 9899:2011],
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Any pointer type may be converted to an integer type. Except as previously specified, the result is implementation-defined. If the result cannot be represented in the integer type, the behavior is undefined. The result need not be in the range of values of any integer type.
See also undefined behavior 24 of Annex J.
These issues arise because the mapping functions for converting a pointer to an integer or an integer to a pointer must be consistent with the addressing structure of the execution environment. For example, not all machines have a flat memory model.
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Please note that this noncompliant code example also violates EXP11-C. Do not make assumptions regarding the layout of structures with bit-fields.
Compliant Solution
Saving a few bits of storage is generally not as important as writing portable code. A struct
can be used to provide room for both the pointer and the flag value. This is portable to machines of different word sizes, both smaller and larger than 32 bits, working even when pointers cannot be represented in any integer type.
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unsigned int *ptr = (unsigned int *) 0xcfcfcfcf; |
Exceptions
INT11-EX1: A null pointer can be converted to an integer; it takes on the value 0. Likewise, a 0 integer can be converted to a pointer; it becomes the null pointer.
INT11-EX2: Any valid pointer to void can be converted to intptr_t
or uintptr_t
and back with no change in value. (This includes the underlying types if intptr_t
and uintptr_t
are typedef
s, and any typedef
s that denote the same types as intptr_t
and uintptr_t
.)
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void h(void) { intptr_t i = (intptr_t)(void *)&i; uintptr_t j = (uintptr_t)(void *)&j; void *ip = (void *)i; void *jp = (void *)j; assert(ip == &i); assert(jp == &j); } |
Risk Assessment
Converting from pointer to integer or vice versa results in unportable code and may create unexpected pointers to invalid memory locations.
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ISE/IEC TR 17961 (Draft) Converting a pointer to integer or integer to pointer [intptrconv]
ISO/IEC TR 24772 "HFC Pointer casting and pointer type changes"
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