...
| Code Block |
|---|
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Contains: 0 1 2 3 4 5 6 7 8 9
Contains: 0 1 3 4 5 6 7 8 9 |
Compliant Solution (Iterator Arithmetic)
Removing a specific element of a container does not require a predicate function but can instead simply use std::vector::erase(), as in this compliant solution:.
| Code Block |
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#include <algorithm>
#include <iostream>
#include <iterator>
#include <vector>
template <typename Iter>
void print_container(Iter B, Iter E) {
std::cout << "Contains: ";
std::copy(B, E, std::ostream_iterator<decltype(*B)>(std::cout, " "));
std::cout << std::endl;
}
void f() {
std::vector<int> v{0, 1, 2, 3, 4, 5, 6, 7, 8, 9};
print_container(v.begin(), v.end());
v.erase(v.begin() + 3);
print_container(v.begin(), v.end());
} |
...
