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Comment: Edited by sciSpider Java v3.0 (sch jp)

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Conversion from int or long to float, or long to double can lead to loss of precision (loss of least significant bits). No run-time runtime exception occurs despite the loss.

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From

To

Description

int or long

integral type T

Sign extend corresponding 2's complement form

char

integral type T

Zero extend representation of char value

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Noncompliant Code Example

In this non-compliant noncompliant example, an int is converted to float. Since a floating point number cannot be precise to 9 digits, the result of subtracting the original from this value is non-zero.

Code Block
bgColor#FFcccc
class wideSample {
  public static void main(String[] args) {
    int big = 1234567890;
    float approx = big;
    System.out.println(big - (int)approx);  //ideally this should be zero but it prints -46
  }
}

Compliant Solution

The significand part of a floating point number can hold at most 23 bit values. Anything above this threshold is discarded due to precision loss, as is demonstrated in this compliant solution.

Code Block
bgColor#ccccff
class wideSample {
  public static void main(String[] args) {
    int big = 1234567890;
                
    float approx = big;
    if(Integer.highestOneBit(big) <= Math.pow(2, 23)) { //the significand can store at most 23 bits
      System.out.println(big - (int)approx);  //always prints zero now
    }
    else {
      //handle error   //precision error
    }
  }
}

Risk Assessment

TODO

Rule

Severity

Likelihood

Remediation Cost

Priority

Level

INT33-J

??

??

??

P??

L??

Automated Detection

TODO

Related Vulnerabilities

Search for vulnerabilities resulting from the violation of this rule on the CERT website.

References

JLS 5.1.2 Widening Primitive Conversion