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double dollar = 1.0; double dime = 0.1; int number = 7; System.out.println (""A dollar less "" + number + "" dimes is $"" + (dollar - number * dime) ); |
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long dollar = 100; long dime = 10; int number = 7; System.out.println (""A dollar less "" + number + "" dimes is "" + (dollar - number * dime) + "" cents"" ); |
This code outputs: A dollar less 7 dimes is 30 cents
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import java.math.BigDecimal; BigDecimal dollar = new BigDecimal(""1.0""); BigDecimal dime = new BigDecimal(""0.1""); int number = 7; System.out.println (""A dollar less "" + number + "" dimes is $"" + (dollar.subtract(new BigDecimal(number).multiply(dime) )) ); |
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This rule appears in the C Secure Coding Standard as FLP02-C. Avoid using floating point numbers when precise computation is needed.
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\[[JLS 05|AA. Java References#JLS 05]\] [Section 4.2.3, Floating-Point Types, Formats, and Values|http://java.sun.com/docs/books/jls/third_edition/html/typesValues.html#4.2.3]
\[[Bloch 08|AA. Java References#Bloch 08]\] Item 48: Avoid {{float}} and {{double}} if exact answers are required
\[[Bloch 05|AA. Java References#Bloch 05]\] Puzzle 2: Time for a Change
\[[Goldberg 91|AA. Java References#Goldberg 91]\] |
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07. Floating Point (FLP) 07. Floating Point (FLP) FLP01-J. Take care in rearranging floating point expressions