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This code attempts to reduce a floating point number to a denormalized value and then restore the value.
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#include <stdio.h>
float x = 1/3.0f;
System.out.println("Original : " + x);
x = x * 7e-45f;
System.out.println("Denormalized? : " + x);
x = x / 7e-45f;
System.out.println("Restored : " + x);
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Do not use code that could use denormalized numbers. When calculations using float produce denormalized numbers, use of double may provide sufficient precision.
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#include <stdio.h>
double x = 1/3.0;
System.out.println("Original : " + x);
x = x * 7e-45;
System.out.println("Denormalized? : " + x);
x = x / 7e-45;
System.out.println("Restored : " + x);
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