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The C Standard, 6.3.2.3, paragraph 7 [ISO/IEC 9899:20112024], states

A pointer to an object or incomplete type may be converted to a pointer to a different object or incomplete type. If the resulting pointer is not correctly aligned for the referenced the referenced type, the behavior is undefined.

See undefined behavior 25.

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The C Standard allows any object pointer to be cast to and from void *. As a result, it is possible to silently convert from one pointer type to another without the compiler diagnosing the problem by storing or casting a pointer to void * and then storing or casting it to the final type. In this noncompliant code example, loop_function() is passed the char pointer loopchar_ptr but returns an object of type int pointer:

int *loop_function(void *v_pointer) {
  /* ... */
  return v_pointer;
}
 
void func(char *loopchar_ptr) {
  int *int_ptr = loop_function(loopchar_ptr);

  /* ... */
}

This example compiles without warning using GCC 4.8 on Ubuntu Linux 14.04. However, vint_pointer can be more strictly aligned than an object of type int char *.

Compliant Solution

Because the input parameter directly influences the return value, and loop_function() returns an object of type int *, the formal parameter v_pointer is redeclared to accept only an object of type int *:

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EXP36-C-EX1: Some hardware architectures have relaxed requirements with regard to pointer alignment. Using a pointer that is not properly aligned is correctly handled by the architecture, although there might be a performance penalty. On such an architecture, improper pointer alignment is permitted but remains an efficiency problem.

The x86 32- and 64-bit architectures usually impose only a performance penalty for violations of this rule, but under some circumstances, noncompliant code can still exhibit undefined behavior. Consider the following program:

#include <stdio.h>
#include <stdint.h>

#define READ_UINT16(ptr)       (*(uint16_t *)(ptr))
#define WRITE_UINT16(ptr, val) (*(uint16_t *)(ptr) = (val))

void compute(unsigned char *b1, unsigned char *b2,
             int value, int range) {
  int i;
  for (i = 0; i < range; i++) {
    int newval = (int)READ_UINT16(b1) + value;
    WRITE_UINT16(b2, newval);
    b1 += 2;
    b2 += 2;
  }
}

int main() {
  unsigned char buffer1[1024];
  unsigned char buffer2[1024];
  printf("Compute something\n");
  compute(buffer1 + 3, buffer2 + 1, 42, 500);
  return 0;
}

This code tries to read short ints (which are 16 bits long) from odd pairs in a character array, which violates this rule. On 32- and 64-bit x86 platforms, this program should run to completion without incident. However, the program aborts with a SIGSEGV due to the unaligned reads on a 64-bit platform running Debian Linux, when compiled with GCC 4.9.4 using the flags  -O3   or  -O2 -ftree-loop-vectorize -fvect-cost-model.

If a developer wishes to violate this rule and use undefined behavior, they must not only ensure that the hardware guarantees the behavior of the object code, but they must also ensure that their compiler, along with its optimizer, also respect these guarantees.

EXP36-C-EX2: If a pointer is known to be correctly aligned to the target type, then a cast to that type is permitted. There are several cases where a pointer is known to be correctly aligned to the target type. The pointer could point to an object declared with a suitable alignment specifier. It could point to an object returned by aligned_alloc(), calloc(), malloc(), or realloc(), as per the C standard, section 7.22.3, paragraph 1  [ISO/IEC 9899:2011].

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Accessing a pointer or an object that is not properly aligned can cause a program to crash or give erroneous information, or it can cause slow pointer accesses (if the architecture allows misaligned accesses).

Automated Detection

Related Vulnerabilities

Search for vulnerabilities resulting from the violation of this rule on the CERT website.

Related Guidelines

Key here (explains table format and definitions)

Bibliography

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