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If a function is reentered during the initialization of a static object inside that function, the behavior of the program is undefined. Please note that this problem is not the same as infinite recursion. For this problem to occur, a function need only recur once.

Wiki Markup\[The C++ Standard, [stmt.dcl], paragraph 4 [ISO/IEC 14882-2003|AA. Bibliography#ISO/IEC 14882-2003]\] Section 6.7, "Declaration Statement" describes the initialization of static and thread storage duration objects. The direct quote is as follows2014], states the following:

The zero-initialization (8.5) of all local objects block-scope variables with static storage duration or thread storage duration (3.7.1) or thread storage duration (3.7.2) is performed before any other initialization takes place. Constant initialization of a local (3.6.2) of a block-scope entity with static storage duration, if applicable, is performed before its block is first entered. An  An implementation is permitted to perform early initialization of other local objects block-scope variables with static or thread or thread storage duration under the same conditions that an implementation is permitted to statically initialize an object initialize a variable with static or thread storage duration in namespace scope (3.6.2). Otherwise such an object is initialized a variable is initialized the first time control passes through its declaration; such an object a variable is considered initialized upon the upon the completion of its initialization. If the initialization exits by throwing an exception, the initialization is initialization is not complete, so it will be tried again the next time control enters the declaration. If control enters the enters the declaration concurrently while the object variable is being initialized, the concurrent execution shall wait for completion for completion of the initialization. If  If control re-enters the declaration recursively while the object variable is being initializedbeing initialized, the behavior is undefined.

Noncompliant Code Example

Do not reenter a function during the initialization of a static variable declaration. If a function is reentered during the constant initialization of a static object inside that function, the behavior of the program is undefined. Infinite recursion is not required to trigger undefined behavior, the function need only recur once as part of the initialization. Due to thread-safe initialization of variables, a single, recursive call will often result in a deadlock due to locking a non-recursive synchronization primitive.

Additionally, the C++ Standard, [basic.start.init], paragraph 2, in part, states the following:

Dynamic initialization of a non-local variable with static storage duration is either ordered or unordered. Definitions of explicitly specialized class template static data members have ordered initialization. Other class template static data members (i.e., implicitly or explicitly instantiated specializations) have unordered initialization. Other non-local variables with static storage duration have ordered initialization. Variables with ordered initialization defined within a single translation unit shall be initialized in the order of their definitions in the translation unit. If a program starts a thread, the subsequent initialization of a variable is unsequenced with respect to the initialization of a variable defined in a different translation unit. Otherwise, the initialization of a variable is indeterminately sequenced with respect to the initialization of a variable defined in a different translation unit. If a program starts a thread, the subsequent unordered initialization of a variable is unsequenced with respect to every other dynamic initialization. Otherwise, the unordered initialization of a variable is indeterminately sequenced with respect to every other dynamic initialization.

Do not create an initialization interdependency between static objects with dynamic initialization unless they are ordered with respect to one another. Unordered initialization, especially prevalent across translation unit boundaries, results in unspecified behavior.

Noncompliant Code Example

This noncompliant example attempts to implement an efficient factorial function using caching. Because the initialization of the static local array cache involves recursion, the behavior of the function is undefined, even though the recursion is not infiniteThis noncompliant code example declares the variable y as a static int. The value of test( x) is assigned to y within the test(int x) function. However, when test(int x) is called with an input that results in reaching the initialization of y more than once, such as the value 12, undefined behavior occurs. Note that this code does not present an infinite recursion and still causes the undefined behavior mentioned.

#include <stdexcept>
 
int test fact(int xi) noexcept(false) {
  x--;
  if (xi < 0 || x > 10) {
    return 0) {
    // Negative factorials are undefined.
    throw std::domain_error("i must be >= 0");
  }
 
  else {
    static int y = test(x);  //<--undefined behavior occurs herestatic const int cache[] = {
    fact(0), fact(1), fact(2), fact(3), fact(4), fact(5),
    fact(6), fact(7), fact(8), fact(9), fact(10), fact(11),
    fact(12), fact(13), fact(14), fact(15), fact(16)
  };
 
  if (i < (sizeof(cache) / sizeof(int))) {
    return ycache[i];
  }
 
  return i > 0 ? i * fact(i - 1) : 1;
}

Implementation

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Details

In the GCC Version 3 compiler, this code will recur as if y were a non-static variable.

In the GCC Version 4 compiler, upon reaching the initialization of y for the second time, the program will terminate with the following message:

terminate called after throwing an instance of
'__gnu_cxx::recursive_init'
  what():  N9__gnu_cxx14recursive_initE
Aborted (core dumped)

Compliant Solution

In this compliant solution, {{y}} is declared before being assigned a value. According to \[[ISO/IEC 14882-2003|AA. Bibliography#ISO/IEC 14882-2003]\] Section 6.7.4, the initialization of {{y}} will have been completed at the end of the declaration and before the assignment of a value, consequently removing the possibility of undefined behavior.

Microsoft Visual Studio 2015 and GCC 6.1.0, the recursive initialization of cache deadlocks while initializing the static variable in a thread-safe manner.

Compliant Solution

This compliant solution avoids initializing the static local array cache and instead relies on zero-initialization to determine whether each member of the array has been assigned a value yet and, if not, recursively computes its value. It then returns the cached value when possible or computes the value as needed.

#include <stdexcept>
 
int fact(int i) noexcept(false) {
   if (i < 0) {
    // Negative factorials are undefined.
    throw std::domain_error("i must be >= 0");
  }

  // Use the lazy-initialized cache.
  static int cache[17];
  if (i < (sizeof(cache) / sizeof(int))) {
    if (0 == cache[i]) {
      cache[i] = i > 0 ? i * fact(i - 1) : 1;
    }
    return cache[i];
  }
 
  return i > 0 ? i * fact(i - 1) : 1;
}

Noncompliant Code Example

In this noncompliant code example, the value of numWheels in file1.cpp relies on c being initialized. However, because c is defined in a different translation unit (file2.cpp) than numWheels, there is no guarantee that c will be initialized by calling get_default_car() before numWheels is initialized by calling c.get_num_wheels(). This is often referred to as the "static initialization order fiasco," and the resulting behavior is unspecified.

// file.h
#ifndef FILE_H
#define FILE_H
 
class Car {
  int numWheels;
 
public:
  Car() : numWheels(4) {}
  explicit Car(int numWheels) : numWheels(numWheels) {}
 
  int get_num_wheels() const { return numWheels; }
};
#endif // FILE_H
 
// file1.cpp
#include "file.h"
#include <iostream>
 
extern Car c;
int numWheels = c.get_num_wheels();
 
int main() {
  std::cout << numWheels << std::endl;
}
 
// file2.cpp
#include "file.h"
 
Car get_default_car() { return Car(6); }
Car c = get_default_car();

Implementation Details

The value printed to the standard output stream will often rely on the order in which the translation units are linked. For instance, with Clang 3.8.0 on x86 Linux, the command clang++ file1.cpp file2.cpp && ./a.out will write 0 while clang++ file2.cpp file1.cpp && ./a.out will write 6.

Compliant Solution

This compliant solution uses the "construct on first use" idiom to resolve the static initialization order issue. The code for file.h and file2.cpp are unchanged; only the static numWheels in file1.cpp is moved into the body of a function. Consequently, the initialization of numWheels is guaranteed to happen when control flows over the point of declaration, ensuring control over the order. The global object c is initialized before execution of main() begins, so by the time get_num_wheels() is called, c is guaranteed to have already been dynamically initialized.

// file.h
#ifndef FILE_H
#define FILE_H

class Car {
  int numWheels;

public:
  Car() : numWheels(4) {}
  explicit Car(int numWheels) : numWheels(numWheels) {}

  int get_num_wheels() const { return numWheels; }
};
#endif // FILE_H

// file1.cpp
#include "file.h"
#include <iostream>

int &get_num_wheels() {
  extern Car c;
  static int numWheels = c.get_num_wheels();
  return numWheels;
}

int main() {
  std::cout << get_num_wheels() << std::endl;
}

// file2.cpp
#include "file.h"

Car get_default_car() { return Car(6); }
Car c = get_default_car();

int test (int x) {
  x--;
  if (x < 0 || x > 10) {
    return 0;
  }
  else {
    static int y;
    y = test(x);  
    return y;
  }
}

Risk Assessment

Recursively reentering a function during the initialization of one of its static objects can result in an attacker being able to cause a crash or denial of service. Indeterminately ordered dynamic initialization can lead to undefined behavior due to accessing an uninitialized object.

Automated Detection

Related Vulnerabilities

Search for vulnerabilities resulting from the violation of this rule on the CERT website.

Bibliography

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Related Guidelines

Bibliography

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DCL37-CPP. Overloaded postfix operators should return const      02. Declarations and Initialization (DCL)      03. Expressions (EXP)Image Added Image Added Image Added