String literals are The type of a narrow string literal is an array of char, and the type of a wide string literal is an array of wchar_t. However, string literals (of both types) are notionally constant and should consequently be protected by const qualification. This recommendation supports rule is a specialization of DCL00-C. Const-qualify immutable objects and also supports STR30-C. Do not attempt to modify string literals.

Adding const qualification may propagate through a program; as you add const qualifiers are added, still more become necessary. This phenomenon is sometimes called "const poisoning." While -poisoning. Const-poisoning can frequently lead to violations of EXP05-C. Do not cast away a const qualification. Although const qualification is a good idea, the costs may outweigh the value when remediating in the remediation of existing code.

...

Noncompliant Code Example (Narrow String Literal)

In the following non-compliant codethis noncompliant code example, the const keyword has been omitted.:

char *c = "Hello";

...

If a statement such as {{c\[0\] = 'C'}} were placed following the above declaration, the code would likely still compile cleanly, but the result of the assignment is undefined as string literals are considered declaration in the noncompliant code example, the code is likely to compile cleanly, but the result of the assignment would be undefined because string literals are considered constant.

Compliant Solution (

...

Immutable Strings)

In this compliant solution, the characters referred to by the pointer c are const-qualified, meaning that any attempts attempt to assign them to different values is an error.:

const char *c = "Hello";

Compliant Solution (

...

Mutable Strings)

In cases where the string is meant to be modified, use initialization instead of assignment. In this compliant solution, c is a modifiable char array which that has been initialized using the contents of the corresponding string literal.:

char c[] = "Hello";

...

Consequently, a statement such as {{c\[0\] = 'C'}} is valid and behaves as ] = 'C' is valid and behaves as expected.

Noncompliant Code Example (Wide String Literal)

In this noncompliant code example, the const keyword has been omitted:

wchar_t *c = L"Hello";

If a statement such as c[0] = L'C' were placed following this declaration, the code is likely to compile cleanly, but the result of the assignment would be undefined because string literals are considered constant.

Compliant Solution (Immutable Strings)

In this compliant solution, the characters referred to by the pointer c are const-qualified, meaning that any attempt to assign them to different values is an error:

wchar_t const *c = L"Hello";

Compliant Solution (Mutable Strings)

In cases where the string is meant to be modified, use initialization instead of assignment. In this compliant solution, c is a modifiable wchar_t array that has been initialized using the contents of the corresponding string literal:

wchar_t c[] = L"Hello";

Consequently, a statement such as c[0] = L'C' is valid and behaves as expected.

Risk Assessment

Modifying string literals causes undefined behavior, resulting in abnormal program termination and denial-of-service vulnerabilities.

Automated Detection

...

Related Vulnerabilities

Search for for vulnerabilities resulting from the violation of this rule on the CERT website.

References:

\[[Corfield 93|AA. C References#Corfield 93]\]
\[[ISO/IEC 9899-1999|AA. C References#ISO/IEC 9899-1999]\] Section 6.7.8, "Initialization"
\[[Lockheed Martin 2005|AA. C References#Lockheed Martin 05]\] AV Rule 151.1

Bibliography

...

Image Added Image Added Image AddedSTR04-A. Use plain char for character data      07. Characters and Strings (STR)       STR06-A. Do not assume that strtok() leaves the parse string unchanged