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Implementation Details

Compiled at -O0 for x86-64 using GCC 7.5 or Clang 8.0 on Ubuntu 18.04 (Linux for x86-64), the preceding example outputs the following when run:

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Because g() has finished executing at the time longjmp() is called, it is no longer on the stack. When do_stuff() is invoked, its stack frame occupies the same memory as the old stack frame of g(). In this case, a was located in the same location as the return address of function g(). The call to memcpy() assignment of b overwrites the return address, so when longjmp() sends control back to function g(), the function returns to the wrong address (in this case, to function bad()).

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jmp_buf buf;

void f(void) {
  int i = 0;
  if (setjmp(buf) != 0) {
    printf("%i\n", i);
    /* ... */
  }
  i = 2;
  g();
}

void g(void) {
  /* ... */
  longjmp(buf, 1);
}

Implementation Details

Calling f() will print 2 if you compile with -O0, but will print 0 if you compile with -O2.  This involves using GCC 7.5 or Clang 8.0 on Ubuntu 18.04 (Linux x86-64).

Compliant Solution

If an object local to the function that invoked setjmp() needs to be accessed after longjmp() returns control to the function, the object should be volatile-qualified:

jmp_buf buf;

void f(void) {
  volatile int i = 0;
  if (setjmp(buf) != 0) {
    printf("%i\n", i);
    /* ... */
  }
  i = 2;
  g();
}

void g(void) {
  /* ... */
  longjmp(buf, 1);
}

This will now correctly print 2 regardless of optimization level.

Risk Assessment

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