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While it has been common practice to Although programmers often use integers and pointers interchangeably in C, pointer-to-integer and integer-to-pointer conversions are implementation-defined. 

Conversions between integers and pointers can have undesired consequences depending on the implementation.

According to the to the C Standard, Section subclause 6.3.2.3 3 [ISO/IEC 9899:20112024],

An integer may be converted to any pointer type. Except as previously specified, the result is implementation-defined, might not be correctly aligned, might not point to an entity of the referenced type, and might be a trap representation.

Any pointer type may be converted to an integer type. Except as previously specified, the result is implementation-defined. If the result cannot be represented in the integer type, the behavior is undefined. The result need not be in the range of values of any integer type.

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Do not convert an integer type to a pointer type if the resulting pointer is incorrectly aligned, does not point to an entity of the referenced type, or is a trap representation.

Do not convert a pointer type to an integer type if the result cannot be represented in the integer type. (See undefined behavior 24.)

These issues arise because the mapping functions for converting a pointer to an integer or an integer to a pointer The mapping between pointers and integers must be consistent with the addressing structure of the execution environment. For Issues may arise, for example, not all machines on architectures that have a flat segmented memory model.

Noncompliant Code Example

This example is noncompliant on The size of a pointer can be greater than the size of an integer, such as in an implementation where pointers are 64 bits and unsigned integers are 32 bits. This code example is noncompliant on such implementations because the result of converting the 64-bit ptr cannot be represented in the 32-bit integer type.:

void f(void) {
  char *ptr;
  /* ... */
  unsigned int number = (unsigned int)ptr;  /* violation */
  /* ... */
}

Compliant Solution

Any valid pointer to void can be converted to intptr_t or uintptr_t and back with no change in value. (see INT11See INT36-EX2.) The C Standard guarantees that a pointer to void may be converted to or from a pointer to any object type and back again and that the result must compare equal to the original pointer. Consequently, converting directly from a char * pointer to a uintptr_t, as in this compliant solution, is allowed on implementations that support the uintptr_t type.

#include <stdint.h>
 
void f(void) {
  char *ptr;
  /* ... */
  uintptr_t number = (uintptr_t)ptr;  
  /* ... */
}

Noncompliant Code Example

In this noncompliant code example, the pointer ptr is converted to an integer value. Both a pointer and an int are assumed to be 32 bits. The high-order 9 bits of the number are used to hold a flag value, and the result is converted back into a pointer. This example is noncompliant on an implementation where pointers are 64 bits and unsigned integers are 32 bits because the result of converting the 64-bit ptr cannot be represented in the 32-bit integer type.

void func(unsigned int flag) {
  char *ptr;
unsigned int flag;
/* ... */
  unsigned int number = (unsigned int)ptr;
  number = (number & 0x7fffff) | (flag << 23);
  ptr = (char *)number;
}

A similar scheme was used in early versions of Emacs, limiting its portability and preventing the ability to edit files larger than 8MB.Please note that this noncompliant code example also violates EXP11-C. Do not make assumptions regarding the layout of structures with bit-fields.

Compliant Solution

Saving a few bits of storage is generally not as important as writing portable code. A struct can be used to provide room This compliant solution uses a struct to provide storage for both the pointer and the flag value. This solution is portable to machines of different word sizes, both smaller and larger than 32 bits, working even when pointers cannot be represented in any integer type. 

struct ptrflag {
  char *pointer;
  unsigned int flag : 9;
} ptrflag;
 
void func(unsigned int flag) {
  char *ptr;
unsigned int flag;
/* ... */
  ptrflag.pointer = ptr;
  ptrflag.flag = flag;
}

Noncompliant Code Example

It is sometimes necessary in low-level kernel or graphics code to access memory at a specific location, requiring a literal integer to pointer conversion. In this noncompliant code, a pointer is set directly to an integer constant, where it is unknown whether the result will be as intended.:

unsigned int *g(void) {
  unsigned int *ptr = 0xcfcfcfcf;
 0xdeadbeef;
  /* ... */
  return ptr;
} 

The result of this assignment is implementation-defined, might not be correctly aligned, might not point to an entity of the referenced type, and might be a trap representation.

Compliant Solution

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Unfortunately this code cannot be made safe while strictly conforming to ISO C.

A particular platform (that is, hardware, operating system, compiler, and Standard C library) might guarantee that a memory address is correctly aligned for the pointer type, and actually contains a value for that type. A common practice is to use addresses that are known to point to hardware that provides valid values.

Exceptions

INT36-C-EX1: The integer value 0

Adding an explicit cast may help the compiler convert the integer value into a valid pointer.

unsigned int *ptr = (unsigned int *) 0xcfcfcfcf;

Exceptions

INT11-EX1: A null pointer can be converted to an integer; it takes on the value 0. Likewise, a 0 integer can be converted to a pointer; it becomes the null pointer.

INT11INT36-C-EX2: Any valid pointer to void can be converted to intptr_t or uintptr_t or their underlying types and back again with no change in value. This includes the Use of underlying types if instead of intptr_t and or uintptr_t are typedefs, and any typedefs that denote the same types as intptr_t and uintptr_t is discouraged, however, because it limits portability.

#include <assert.h>
#include <stdint.h>
 
void h(void) {
  intptr_t i = (intptr_t)(void *)&i;
  uintptr_t j = (uintptr_t)(void *)&j;
 
  void *ip = (void *)i;
  void *jp = (void *)j;
 
  assert(ip == &i);
  assert(jp == &j);
}

Risk Assessment

Converting from pointer to integer or vice versa results in unportable code that is not portable and may create unexpected pointers to invalid memory locations.

Automated Detection

Related Vulnerabilities

Search for vulnerabilities resulting from the violation of this rule on the CERT website.

Related Guidelines

Key here (explains table format and definitions)

CERT-CWE Mapping Notes

Key here for mapping notes

CWE-758 and INT36-C

Independent( INT34-C, INT36-C, MEM30-C, MSC37-C, FLP32-C, EXP33-C, EXP30-C, ERR34-C, ARR32-C)

CWE-758 = Union( INT36-C, list) where list =

• Undefined behavior that results from anything other than integer <-> pointer conversion

CWE-704 and INT36-C

CWE-704 = Union( INT36-C, list) where list =

• Incorrect (?) typecast that is not between integers and pointers

CWE-587 and INT36-C

Intersection( CWE-587, INT36-C) =

• Setting a pointer

...

• to an integer value that is ill-defined (trap representation, improperly aligned, mis-typed, etc)

CWE-587

...

– INT36-C =

• Setting a pointer to a valid integer value (eg points to an object of the correct t ype)

INT36-C – CWE-587 =

• Illegal pointer-to-integer conversion

Intersection(INT36-C,CWE-466) =  ∅  

Intersection(INT36-C,CWE-466) =  ∅

An example explaining the above two equations follows:

static char x[3];

char* foo() {

  int x_int = (int) x; // x_int = 999 eg

  return x_int + 5; // returns 1004 , violates CWE 466

}

...

int y_int = foo(); // violates CWE-466

char* y = (char*) y_int; //  // well-defined but y may be invalid, violates INT36-C

char c = *y; // indeterminate value, out-of-bounds read, violates CWE-119

Bibliography

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