EXP36-C. Do not cast pointers into more strictly aligned pointer types

Do not convert a pointer value to a pointer type that is more strictly aligned than the referenced type. Different alignments are possible for different types of objects. If the type-checking system is overridden by an explicit cast or the pointer is converted to a void pointer (void *) and then to a different type, the alignment of an object may be changed.

The C Standard, 6.3.2.3, paragraph 7 [ISO/IEC 9899:2011], states:

A pointer to an object or incomplete type may be converted to a pointer to a different object or incomplete type. If the resulting pointer is not correctly aligned for the referenced type, the behavior is undefined.

See undefined behavior 25.

If the misaligned pointer is dereferenced, the program may terminate abnormally. On some architectures, the cast alone may cause a loss of information even if the value is not dereferenced if the types involved have differing alignment requirements.

Noncompliant Code Example

In this noncompliant example, the char pointer &c is converted to the more strictly aligned int pointer ip. On some implementations, cp will not match &c. As a result, if a pointer to one object type is converted to a pointer to a different object type, the second object type must not require stricter alignment than the first.

#include <assert.h>
 
void func(void) {
  char c = 'x';
  int *ip = (int *)&c; /* This can lose information */
  char *cp = (char *)ip;

  /* Will fail on some conforming implementations */
  assert(cp == &c);
}

Compliant Solution (Intermediate Object)

In this compliant solution, the char value is stored into an object of type int so that the pointer's value will be properly aligned:

#include <assert.h>
 
void func(void) {
  char c = 'x';
  int i = c;
  int *ip = &i;

  assert(ip == &i);
}

Compliant Solution (C11, alignas())

This compliant solution uses the alignment specifier to declare the char object c with the same alignment as that of an object of type int. As a result, the two pointers reference equally aligned pointer types:

#include <stdalign.h>
#include <assert.h>
 
void func(void) {
  /* Align c to the alignment of an int */
  alignas(int) char c = 'x';
  int *ip = (int *)&c; 
  char *cp = (char *)ip;
  /* Both cp and &c point to equally aligned objects */
  assert(cp == &c);
}

Noncompliant Code Example

The C Standard allows any object pointer to be cast to and from void *. As a result, it is possible to silently convert from one pointer type to another without the compiler diagnosing the problem by storing or casting a pointer to void * and then storing or casting it to the final type. In this noncompliant code example, loop_function() is passed the char pointer loop_ptr but returns an object of type int pointer:

int *loop_function(void *v_pointer) {
  /* ... */
  return v_pointer;
}
 
void func(char *loop_ptr) {
  int *int_ptr = loop_function(loop_ptr);

  /* ... */
}

This example compiles without warning. However, v_pointer can be more strictly aligned than an object of type int *.

Compliant Solution

Because the input parameter directly influences the return value, and loop_function() returns an object of type int *, the formal parameter v_pointer is redeclared to accept only an object of type int *:

int *loop_function(int *v_pointer) {
  /* ... */
  return v_pointer;
}
 
void func(int *loop_ptr) {
  int *int_ptr = loop_function(loop_ptr);

  /* ... */
}

Another solution is to ensure that loop_ptr points to an object returned by malloc() because this object is guaranteed to be suitably aligned for the storage of any type of object. However, this subtlety is easily missed when the program is modified in the future. It is easier and safer to let the type system document the alignment needs.

Noncompliant Code Example

Some architectures require that pointers are correctly aligned when accessing objects larger than a byte. However, it is common in system code that unaligned data (for example, the network stacks) must be copied to a properly aligned memory location, such as in this noncompliant code example:

#include <string.h>
 
struct foo_header {
  int len;
  /* ... */
};
 
void func(char *data, size_t offset) {
  struct foo_header *tmp;
  struct foo_header header;

  tmp = data + offset;
  memcpy(&header, tmp, sizeof(header));

  /* ... */
}

Assigning an unaligned value to a pointer that references a type that needs to be aligned is undefined behavior. An implementation may notice, for example, that tmp and header must be aligned and use an inline memcpy() that uses instructions that assume aligned data.

Compliant Solution

This compliant solution avoids the use of the foo_header pointer:

#include <string.h>
 
struct foo_header {
  int len;
  /* ... */
};
  
void func(char *data, size_t offset) {
  struct foo_header header; 
  memcpy(&header, data + offset, sizeof(header));

  /* ... */
}

Exceptions

EXP36-EX1: Some hardware architectures have relaxed requirements with regard to pointer alignment. Using a pointer that is not properly aligned is correctly handled by the architecture, although there might be a performance penalty. On such an architecture, improper pointer alignment is permitted but remains an efficiency problem.

Risk Assessment

Accessing a pointer or an object that is not properly aligned can cause a program to crash or give erroneous information, or it can cause slow pointer accesses (if the architecture allows misaligned accesses).

Automated Detection

Related Vulnerabilities

Search for vulnerabilities resulting from the violation of this rule on the CERT website.

Related Guidelines

Bibliography