It is important to note that the signal()
function behaves a little differently in Windows than it does on Linux/BSD systems. When a signal handler is installed with the signal()
function in Windows, after the signal is triggered once, the default action is restored for that signal. Conversely, Linux/BSD systems leave the signal handler defined by the user in place until it is explicitly removed.
Implementation Details
The following code runs differently on Linux and Windows.
#include <stdio.h> #include <signal.h> volatile sig_atomic_t e_flag = 0; void handler(int signum) { e_flag = 1; } int main() { signal(SIGINT, handler); while(!e_flag) {} puts("Escaped from first while()"); e_flag = 0; while(!e_flag) {} puts("Escaped from second while()"); return 0; }
Linux
When compiled with gcc 3.4.4 on Red Hat Linux, the signal handler is automatically reinstalled upon handler execution.
% ./SIG01-A ^C Escaped from first while() ^C Escaped from second while() %
Windows
When compiled with Microsoft Visual Studio 2005, version 8.0, the signal handler is not automatically reinstalled.
> SIG01-A.exe ^C Escaped from first while() ^C >
The second interrupt executes the default action for SIGINT
, which is to terminate program execution.
If you desire the handler to persist on a Windows system, a standards-compliant solution is to rebind the signal to the handler in the first line of the handler itself:
void handler(int signum) { signal(signum, handler); /* rest of handling code */ }
References
[[ISO/IEC 9899-1999TR2]] "The signal
function"