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Some expressions involve operands that are unevaluated. According to the C++ Standard, [expr], paragraph 8 [ISO/IEC 14882-2014]:

In some contexts, unevaluated operands appear. An unevaluated operand is not evaluated. An unevaluated operand is considered a full-expression. [Note: In an unevaluated operand, a non-static class member may be named (5.1) and naming of objects or functions does not, by itself, require that a definition be provided. — end note]

Because an unevaluated operand in an expression is not evaluated, no side effects from that operand will be triggered. Reliance on those side effects will result in unexpected behavior. Do not rely on side effected in unevaluated operands.

The following expressions do not evaluate their operands: sizeof()typeid()noexcept()decltype(), and declval().

Noncompliant Code Example (sizeof)

In this noncompliant code example, the expression a++ is not evaluated:

#include <iostream>
void f() {
  int a = 14;
  int b = sizeof(a++);
  std::cout << a << ", " << b << std::endl;
}

Consequently, the value of a after b has been initialized is 14.

Compliant Solution (sizeof)

In this compliant solution, the variable a is incremented outside of the sizeof operator:

#include <iostream>
void f() {
  int a = 14;
  int b = sizeof(a);
  ++a;
  std::cout << a << ", " << b << std::endl;
}

Noncompliant Code Example (decltype)

In this noncompliant code example, the call to g() is not evaluated within the decltype specifier:

#include <iostream>

static int glob = 100;

int g() { return ++glob; }

void f() {
  decltype(g()) h = 12;
  std::cout << glob;
}

Consequently, the value of glob remains 14. The function call syntax is used within decltype to distinguish between the return type of g() and the function type of g, but the call is never evaluated.

Compliant Solution (decltype)

In this compliant solution, g() is called outside of the decltype specifier, so that it is evaluated as desired:

#include <iostream>

static int glob = 100;

int g() { return ++glob; }

void f() {
  decltype(g()) h = 12;
  g();
  std::cout << glob;
}

Risk Assessment

If expressions that appear to produce side effects are an unevaluated operand, the results may be different than expected. Depending on how this result is used, it can lead to unintended program behavior.

Rule

Severity

Likelihood

Remediation Cost

Priority

Level

EXP32-CPP

Low

Unlikely

Low

P3

L3

Automated Detection

Tool

Version

Checker

Description

    

Related Vulnerabilities

Search for vulnerabilities resulting from the violation of this rule on the CERT website.

Related Guidelines

Bibliography

[ISO/IEC 14882-2014]Clause 5, "Expressions"
20.2.5, "Function template declval
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