An object is characterized by its identity (location in memory) and state (actual data). While the ==
operator compares only the identities of two objects (to check if both the references are actually the same object), the equals
method defined in java.lang.Object
can compare the state as well, when customized by overriding it.
The equals
method only applies to objects, not primitives. Also, immutable objects do not need to override equals. There is no need to override equals
if checking logical equality is not useful. Enumerated types are an example. If a subclass inherits an implementation of equals
from a superclass and does not need additional functionality, overriding equals()
can be forgone.
The general usage contract for equals()
as specified by the Java Language Specification [[JLS 05]] says:
- It is reflexive: For any reference value x,
x.equals(x)
must return true. - It is symmetric: For any reference values x and y,
x.equals(y)
must return true if and only if y.equals(x) returns true. - It is transitive: For any reference values x, y, and z, if
x.equals(y)
returns true andy.equals(z)
returns true, thenx.equals(z)
must return true. - It is consistent: For any reference values x and y, multiple invocations of
x.equals(y)
consistently return true or consistently return false, provided no information used in equals comparisons on the object is modified. - For any non-null reference value x,
x.equals(null)
must return false.
Do not violate any of these five conditions while overriding the equals
method. Mistakes resulting from a violation of to the first condition are infrequent; it is consequently omitted from this discussion. The second and third conditions are highlighted. The rule for consistency implies that mutable objects may not satisfy the equals
contract. It is good practice to avoid defining equals()
implementations that use unreliable data sources such as IP addresses [[Bloch 08]] and caches. The final condition about the comparison with null
is typically violated when the equals()
code throws an exception instead of returning false
. Because this does not constitute a security vulnerability, it is beyond the scope of this discussion.
Noncompliant Code Example
This noncompliant code example violates the second condition in the contract (symmetry). This requirement means that if one object is equal to another then the other must also be equal to this one. Consider a CaseInsensitiveString
class that defines a String
and overrides the equals
method. The CaseInsensitiveString
knows about ordinary strings but the String
class has no idea about case-insensitive strings. As a result, s.equalsIgnoreCase(((CaseInsensitiveString)o).s)
returns true but s.equalsIgnoreCase((String)o)
always returns false.
public final class CaseInsensitiveString { private String s; public CaseInsensitiveString(String s) { if (s == null) throw new NullPointerException(); this.s = s; } //This method violates asymmetry public boolean equals(Object o) { if (o instanceof CaseInsensitiveString) return s.equalsIgnoreCase(((CaseInsensitiveString)o).s); if (o instanceof String) return s.equalsIgnoreCase((String)o); return false; } public static void main(String[] args) { CaseInsensitiveString cis = new CaseInsensitiveString("Java"); String s = "java"; System.out.println(cis.equals(s)); //returns true System.out.println(s.equals(cis)); //returns false } }
Compliant Solution
Do not try to inter-operate with String
from the equals
method. The new equals
method is highlighted in this compliant solution.
public final class CaseInsensitiveString { private String s; public CaseInsensitiveString(String s) { if (s == null) throw new NullPointerException(); this.s = s; } public boolean equals(Object o) { return o instanceof CaseInsensitiveString && ((CaseInsensitiveString)o).s.equalsIgnoreCase(s); } public static void main(String[] args) { CaseInsensitiveString cis = new CaseInsensitiveString("Java"); String s = "java"; System.out.println(cis.equals(s)); //returns false now System.out.println(s.equals(cis)); //returns false now } }
Noncompliant Code Example
This noncompliant code example violates transitivity though it satisfies the symmetry condition. In the first print statement, the comparison between p1
and p2
returns true
, in the second, the comparison between p2
and p3
returns false
and in the third, the comparison between p1
and p3
returns false
. This is counter intuitive as p1
and p2
must compare equal when they are both equal to a common object. A practical implementation issue is intermingling of java.sql.Timestamp
and java.util.Date
classes. There is a disclaimer about the erratic behavior in the documentation for the Timestamp
class.
public class Card { private final int number; public Card(int number) { this.number = number; } public boolean equals(Object o) { if (!(o instanceof Card)) return false; Card c = (Card)o; return c.number == number; } } class XCard extends Card { private String type; public XCard(int number, String type) { super(number); this.type = type; } public boolean equals(Object o) { if (!(o instanceof Card)) return false; //normal Card, do not compare type if (!(o instanceof XCard)) return o.equals(this); //It is an XCard, compare type as well XCard xc = (XCard)o; return super.equals(o) && xc.type == type; } public static void main(String[] args) { XCard p1 = new XCard(1, "type1"); Card p2 = new Card(1); XCard p3 = new XCard(1, "type2"); System.out.println(p1.equals(p2)); //returns true System.out.println(p2.equals(p3)); //returns true System.out.println(p1.equals(p3)); //returns false, violating transitivity } }
Compliant Solution
It is currently not possible to extend an instantiable class (as opposed to an abstract
class) and add a value or field in the subclass while preserving the equals contract. This implies that composition must be preferred over inheritance. This technique does qualify as a reasonable workaround [[Bloch 08]]. It can be implemented by giving the XCard
class a private card
field and providing a a public viewCard
method.
public class Card { private final int number; public Card(int number) { this.number = number; } public boolean equals(Object o) { if (!(o instanceof Card)) return false; Card c = (Card)o; return c.number == number; } } class XCard extends Card { private String type; private Card card; public XCard(int number, String type) { super(number); this.type = type; } public Card viewCard() { return card; } public boolean equals(Object o) { if (!(o instanceof XCard)) return false; XCard cp = (XCard)o; return cp.card.equals(card) && cp.type.equals(type); } public static void main(String[] args) { XCard p1 = new XCard(1, "type1"); Card p2 = new Card(1); XCard p3 = new XCard(1, "type2"); System.out.println(p1.equals(p2)); //returns false System.out.println(p2.equals(p3)); //returns false System.out.println(p1.equals(p3)); //returns false } }
"There are some classes in the Java platform libraries that do extend an instantiable class and add a value component. For example, java.sql.Timestamp
extends java.util.Date
and adds a nanoseconds field. The equals implementation for Timestamp
does violate symmetry and can cause erratic behavior if Timestamp
and Date
objects are used in the same collection or are otherwise intermixed." [[Bloch 08]]
Risk Assessment
Violating the general contract when overriding the equals()
method can lead to unexpected results.
Rule |
Severity |
Likelihood |
Remediation Cost |
Priority |
Level |
---|---|---|---|---|---|
MET30-J |
low |
unlikely |
medium |
P2 |
L3 |
Automated Detection
TODO
Related Vulnerabilities
Search for vulnerabilities resulting from the violation of this rule on the CERT website.
References
[[API 06]] method equals()
[[Bloch 08]] Item 8: Obey the general contract when overriding equals
[[Darwin 04]] 9.2 Overriding the equals method
MET03-J. For methods that return an array or collection prefer returning an empty array or collection over a null value 09. Methods (MET) MET31-J. Ensure that hashCode() is overridden when equals() is overridden