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Calling the signal() function in a multithreaded program is undefined behavior according to C11 (Section 7.14.1.1, paragraph 7).

This rule is a specific instance of SIG02-C. Avoid using signals to implement normal functionality.

Noncompliant Code Example

This code sets a signal handler, while also setting a child thread to do work. This results in undefined behavior.

volatile sig_atomic_t flag = 0;

void handler(int signum) {
  flag = 1;
}


void func(void *data) {  // keep running until user sends SIGUSR1
  while (!flag) {
    /* ... */
  }
}


int main(void) {
  signal(SIGUSR1, handler); // Undefined!
  int result;
  thrd_t thread;
  
  int result;
  if ((result = thrd_create(&tid, func, NULL)) != thrd_success) {
    /* Handle Error */
  }

  /* ... */

  return 0;
}

Compliant Solution

This code dispenses with the signal handler, and uses an atomic_flag to indicate when the child thread should terminate its loop.

atomic_flag flag = ATOMIC_VAR_INIT;


void func(void *data) {  // keep running until user sends SIGUSR1
  while (!flag) {
    /* ... */
  }
}


int main(void) {
  int result;
  thrd_t thread;
  
  int result;
  if ((result = thrd_create(&tid, func, NULL)) != thrd_success) {
    /* Handle Error */
  }


  /* ... */


  /* Set flag when done */
  while (!atomic_flag_test_and_set( &flag)) { /* try again */ }


  return 0;
}

Exceptions

CON37:EX0: Platforms that provide defined behavior when multithreaded programs use custom signal handlers are exempt from this rule. This would include POSIX, for example.

Risk Assessment

Mixing signals and threads causes undefined behavior.

Rule

Severity

Likelihood

Remediation Cost

Priority

Level

CON37-C

low

probable

low

P6

L2

Bibliography

[ISO/IEC 9899:2011]


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