The signal()
function behaves differently in Windows than it does on Linux/BSD systems. When a signal handler is installed with the signal()
function in Windows, the default action is restored for that signal after the signal is triggered. Conversely, Linux/BSD systems leave the signal handler defined by the user in place until it is explicitly removed.
Non-Compliant Code Example (Windows)
This non-complaint code example fails to persist the signal handler on Windows platforms.
#include <stdio.h> #include <signal.h> volatile sig_atomic_t e_flag = 0; void handler(int signum) { e_flag = 1; } int main(void) { signal(SIGINT, handler); while(!e_flag) {} puts("Escaped from first while()"); e_flag = 0; while(!e_flag) {} puts("Escaped from second while()"); return 0; }
When compiled with gcc 3.4.4 and executed under Red Hat Linux, the signal handler is automatically reinstalled upon handler execution.
% ./SIG01-A ^C Escaped from first while() ^C Escaped from second while() %
When compiled with Microsoft Visual Studio 2005 version 8.0 and executed under Windows the signal handler is not automatically reinstalled.
> SIG01-A.exe ^C Escaped from first while() ^C >
The second interrupt executes the default action for SIGINT
, which is to terminate program execution.
Non-Compliant Code Example
A C99-compliant solution to persist the handler on a Windows system is to rebind the signal to the handler in the first line of the handler itself.
void handler(int signum) { signal(signum, handler); /* rest of handling code */ }
References
[[ISO/IEC 9899-1999TR2]] "The signal
function"