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It is possible that an exception gets thrown in the finally block even though it escapes detection at compile time. This can prevent other clean-up statements from getting executed.

Non-Compliant Code Example

The finally clause closes the reader object in this non-compliant example. However, it is incorrectly assumed that the statements within the finally block cannot throw exceptions. Notably, close() can throw an IOException which in turn prevents any subsequent clean-up lines from getting executed. This is not detected at compile time since close() throws the same exception type as read or write.

class Login {
  static void checkPassword(String password_file) throws IOException {
  
    StringBuffer fileData = new StringBuffer(1000);
    BufferedReader reader = new BufferedReader(new FileReader(password_file));

    try {
          int n;
          char[] passwd = new char[1024];
          while ((n = reader.read(passwd)) >= 0) {
            String readData = String.valueOf(passwd, 0, n);
            fileData.append(readData);
            passwd = new char[1024];
          }
          String realPassword = "javac<at:var at:name="f3b" />b3";
          System.out.println(fileData.toString());
        
          if (fileData.toString().equals(realPassword)) {
            System.out.println("Login successful");
          }
          else {
            System.out.println("Login failed");
          }
    } finally {
      reader.close();
      //other clean-up code 
    }
}

  public static void main(String[] args) throws IOException {
    String path = "c:\\password.txt";
    checkPassword(path);
  }
}

Compliant Solution

This compliant solution correctly places the close() statement in a try-catch block. Thus an IOException can be handled without letting it propagate any further.

class Login {
  static void checkPassword(String password_file) throws IOException {
  
    StringBuffer fileData = new StringBuffer(1000);
    BufferedReader reader = new BufferedReader(new FileReader(password_file));

    try {
          int n;
          char[] passwd = new char[1024];
          while ((n = reader.read(passwd)) >= 0) {
            String readData = String.valueOf(passwd, 0, n);
            fileData.append(readData);
            passwd = new char[1024];
          }
          String realPassword = "javac<at:var at:name="f3b" />b3";
          System.out.println(fileData.toString());
        
          if (fileData.toString().equals(realPassword)) {
            System.out.println("Login successful");
          }
          else {
            System.out.println("Login failed");
          }
    } finally {
      try {     //enclose in try-catch block
        reader.close();
        //other clean-up code 
      }catch (IOException ie) {ie.getMessage()}
    }
}

  public static void main(String[] args) throws IOException {
    String path = "c:\\password.txt";
    checkPassword(path);
  }
}

References

Java Puzzlers 5.41
Java I/O

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