During initialization of a shared object, the object must remain exclusive to the thread constructing it. However, once the object is initialized, it can be safely published. That is, it can be made visible to other threads. The [Java Memory Model] allows multiple threads to observe the object after its initialization has begun, but before it has concluded. Consequently, it is important to ensure that a partially initialized object is not published.
This guideline is similar to [CON14-J. Do not let the "this" reference escape during object construction]. In this guideline, a reference to a partially initialized member object instance is published before initialization is over, instead of the this
reference of the current object.
Noncompliant Code Example
This noncompliant code example uses an initialize()
method to construct a Helper
object inside class Foo
, and initialize the field helper
accordingly.
class Foo { private Helper helper; public Helper getHelper() { return helper; } public void initialize() { helper = new Helper(42); } } public class Helper { private int n; public Helper(int n) { this.n = n; } // ... }
Suppose two or more threads can access the field helper
using the getHelper()
method, and initialize()
has not been called yet. Consequently, all threads will see the helper
field as uninitialized. Later, if one thread calls initialize()
, and another calls getHelper()
, the second thread may either see the helper
reference as null
, observe a fully-initialized Helper
object with the n
field set to 42, or observe a partially-initialized Helper
object with an n
that has not been initialized yet, and which contains the default value 0
.
In particular, the [Java Memory Model (JMM)] permits compilers to allocate memory for the new Helper
object and assign it to the helper
field before initializing it. In other words, the compiler can reorder the write to the instance field helper
with the write that initializes the object Helper
(that is, this.n = n
) such that the former occurs first. This introduces a race window during which other threads may see a partially-initialized Helper
object instance.
There is another consideration in that if two threads both call initialize()
, then two Helper
objects will be created, with one eventually being garbage-collected. This is a performance, not a correctness issue because n
always contains the value 42.
Compliant Solution (synchronization)
The reference of a partially-constructed object can be prevented from being made visible by using method synchronization.
class Foo { private Helper helper; public synchronized Helper getHelper() { return helper; } public synchronized void initialize() { helper = new Helper(42); } }
Synchronizing both methods guarantees that they will never run simultaneously in different threads. If one thread were to call initialize()
just before another thread calls getHelper()
, the synchronized initialize()
method will always finish first. Furthermore, this establishes a [happens-before relationship] between the two threads. This guarantees that the thread calling getHelper()
sees the fully initialized Helper
object or none at all (helper
may contain a null
reference). This approach guarantees proper publication for both immutable and mutable members.
Compliant Solution (final
field)
If the helper
field is declared as final
, it is guaranteed to be fully constructed before its reference is made visible.
class Foo { private final Helper helper; public Helper getHelper() { return helper; } public Foo() { helper = new Helper(42); } }
However, now the compiler disallows setting the helper
field to a new object using the initialize()
method. Instead, a constructor is required to initialize helper
.
According to the Java Language Specification [[JLS 05]], section 17.5.2 "Reading Final Fields During Construction":
A read of a
final
field of an object within the thread that constructs that object is ordered with respect to the initialization of that field within the constructor by the usual happens-before rules. If the read occurs after the field is set in the constructor, it sees the value thefinal
field is assigned, otherwise it sees the default value.
Consequently, the reference to the helper
field should not be published before class Foo
's constructor has finished its initialization (see [CON14-J. Do not let the "this" reference escape during object construction]).
Compliant Solution (final
field and thread-safe composition)
Some collection classes provide thread-safety of accesses to contained elements. If the Helper
object is inserted into such a collection, it is guaranteed to be fully initialized before its reference is made visible. This compliant solution encases the helper
field in a Vector<Helper>
.
class Foo { private final Vector<Helper> helper; public Foo() { helper = new Vector<Helper>(); } public Helper getHelper() { if (helper.isEmpty()) { initialize(); } return helper.elementAt(0); } public synchronized void initialize() { if (helper.isEmpty()) { helper.add(new Helper(42)); } } }
The helper
field is declared as final
to guarantee that the vector is created before any accesses take place. It can be suitably initialized using the initialize()
method. The initialize()
method is synchronized, and provides a check to ensure that exactly one Helper
object is added to the vector. The getHelper()
method needs no synchronization in the general case of returning the Helper
, however, if it is invoked before initialize()
, it may ensure that the vector contains the Helper
instance to avoid a null-pointer dereference. Consequently, it invokes initialize()
if the vector is still empty.
Compliant Solution (static initialization)
In this compliant solution, the helper
field is initialized in a static
block. When initialized statically, an object is guaranteed to be fully initialized before its reference is made visible.
cite JLS section here
class Foo { private static final Helper helper = new Helper(42); public static Helper getHelper() { return helper; } }
This requires the helper
field to be declared static
. Although not strictly necessary, it is recommended that the field be declared final
to sufficiently document the class's immutability property.
According to JSR-133 [[JSR-133 04]], 9.2.3 Static Final Fields:
The rules for class initialization ensure that any thread that reads a
static
field will be synchronized with the static initialization of that class, which is the only place wherestatic final
fields can be set. Thus, no special rules in the JMM are needed forstatic final
fields.
Compliant Solution (immutable object, volatile
reference)
The Java memory model guarantees that any final
fields of the object will be fully initialized before a published object becomes visible [[Goetz 06]]. By making n
final, we can render the Helper
class [immutable]. Furthermore, if the helper
field is declared volatile
, the Helper
's reference is guaranteed to be made visible to any thread that calls getHelper()
after Helper
has been fully initialized.
class Foo { private volatile Helper helper; public Helper getHelper() { return helper; } public void initialize() { helper = new Helper(42); } } // Immutable Helper public final class Helper { private final int n; public Helper(int n) { this.n = n; } // ... }
An alternative is to use a public static
factory method in class Helper
to create a new instance of Helper
. The Helper
instance is created using a private
constructor.
// Immutable Helper final class Helper { // Class is not required to be public in this case private final int n; private Helper(int n) { this.n = n; } public static Helper getHelper() { Helper helper = new Helper(42); return helper; } // ... }
This compliant solution requires that helper
be declared as volatile
and class Helper
be immutable. If it were not immutable, the code would violate [CON11-J. Do not assume that declaring an object volatile guarantees visibility of its members] and additional synchronization would be required to fix it (see the next compliant solution). And if the helper
field were not volatile
, it would violate [CON09-J. Ensure visibility of shared references to immutable objects]. See this rule for more information on how to safely publish immutable objects.
Compliant Solution (mutable thread-safe object, volatile
reference)
If Helper
is mutable, but thread-safe, it can be safely published by declaring the helper
field in class Foo
as volatile
.
class Foo { private volatile Helper helper; public Helper getHelper() { return helper; } public void initialize() { helper = new Helper(42); } } // Mutable but thread-safe Helper public class Helper { private volatile int n; public Helper(int n) { this.n = n; } public synchronized void setN(int value) { n = value; } }
Because the state of the Helper
object can be changed after its construction, additional locking is necessary to ensure that all threads see the most recent value of n
after the initial publication. See [CON11-J. Do not assume that declaring an object volatile guarantees visibility of its members] for more information. This is typically the case when a mutable member object is expected to continually publish its most recent state when its reference is declared volatile
. Consequently, in this compliant solution, the setN()
method needs to be synchronized.
In the absence of proper synchronization in class Helper
, the use of volatile
in class Foo
guarantees the visibility of only the initial publication of Helper
and not of subsequent state changes. Consequently, volatile
is not useful for publishing thread-unsafe objects.
When helper
in class Foo
is not declared as volatile
, the field n
should be declared as volatile
so that a happens-before relationship is established between the initialization of n
and the write of Helper
to the field helper
. This is in compliance with [CON11-J. Do not assume that declaring an object volatile guarantees visibility of its members]. This is only required when the caller (class Foo
) cannot be trusted to declare helper
as volatile
.
please double check this para
Exceptions
EX1: This excption uses a volatile
initialized
flag, as recommended by [CON28-J. Prevent partially initialized objects from being used].
public class Helper { private int n; private volatile boolean initialized; // Defaults to false public Helper(int n) { this.n = n; this.initialized = true; } public void doSomething() { if(!initialized) { throw new SecurityException("Cannot use partially initialized instance"); } // ... } // ... }
This ensures that even if the reference to the Helper
object instance is published before its initialization is over, the instance is unusable. This is because every method within Helper
checks the flag to determine whether the initialization has finished. This approach is more useful when the caller (Foo
) is untrusted and consequently, may not declare the helper
field as volatile
.
Risk Assessment
Failing to synchronize access to shared mutable data can cause different threads to observe different states of the object or a partially initialized object.
Rule |
Severity |
Likelihood |
Remediation Cost |
Priority |
Level |
---|---|---|---|---|---|
CON26-J |
medium |
probable |
medium |
P8 |
L2 |
Automated Detection
TODO
Related Vulnerabilities
Search for vulnerabilities resulting from the violation of this rule on the CERT website.
References
[[API 06]]
[[Bloch 01]] Item 48: "Synchronize access to shared mutable data"
[[Goetz 06]] Section 3.5.3 "Safe Publication Idioms"
[[Goetz 07]] Pattern #2: "one-time safe publication"
[[JPL 06]], 14.10.2. Final Fields and Security:
[[Pugh 04]]
[!The CERT Sun Microsystems Secure Coding Standard for Java^button_arrow_left.png!] [!The CERT Sun Microsystems Secure Coding Standard for Java^button_arrow_up.png!] [!The CERT Sun Microsystems Secure Coding Standard for Java^button_arrow_right.png!]