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Bitwise shifts include left-shift operations of the form shift-expression << additive-expression and right-shift operations of the form shift-expression >> additive-expression. The integer promotions are performed on the operands, each of which has an integer type. The type of the result is that of the promoted left operand. If the value of the right operand is negative or is greater than or equal to the width of the promoted left operand, the behavior is undefined. See also undefined behavior 48 51 of Annex J of C99C11.

In almost every case, an attempt to shift by a negative number of bits or by more bits than exist in the operand indicates a bug (logic error). This is different from overflow, where there is simply a representational deficiency. (See rule INT32-C. Ensure that operations on signed integers do not result in overflow.)

Noncompliant Code Example (Left Shift, Signed Type)

The result of E1 << E2 is E1 left-shifted E2 bit positions; vacated bits are filled with zeros. If E1 has a signed type and nonnegative value and E1 * 2E2 is representable in the result type, then that is the resulting value; otherwise, the behavior is undefined.

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This noncompliant code example can result in undefined behavior because there is no check to ensure that left and right operands have nonnegative values and that the right operand is less than or equal to the width of the promoted left operand.

int si1;
int si2;
int sresult;

/* Initialize si1 and si2 */

sresult = si1 << si2;

Shift operators , and other bitwise operators , should only be used with only with unsigned integer operands , in accordance with recommendation INT13-C. Use bitwise operators only on unsigned operands.

Noncompliant Code Example (Left Shift, Unsigned Type)

The result of E1 << E2 is E1 left-shifted E2 bit positions; vacated bits are filled with zeros. According to C99the C standard, if E1 has an unsigned type, the value of the result is E1 * 2E2, reduced modulo one more than the maximum value representable in the result type.

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unsigned int ui1;
unsigned int ui2;
unsigned int uresult;

/* Initialize ui1 and ui2 */

uresult = ui1 << ui2;

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unsigned int ui1;
unsigned int ui2;
unsigned int uresult;

/* Initialize ui1 and ui2 */

if (ui2 >= sizeof(unsigned int)*CHAR_BIT) {
  /* handle error condition */
} else {
  uresult = ui1 << ui2;
}

Modulo behavior resulting from left-shifting an unsigned integer type is permitted by this standard.

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The result of E1 >> E2 is E1 right-shifted E2 bit positions. If E1 has an unsigned type or if E1 has a signed type and a nonnegative value, the value of the result is the integral part of the quotient of E1 / 2E2. If E1 has a signed type and a negative value, the resulting value is implementation defined and can be either an arithmetic (signed) shift:

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or a logical (unsigned) shift:

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This noncompliant code example fails to test whether the right operand is greater than or equal to the width of the promoted left operand, allowing undefined behavior.

unsigned int ui1;
unsigned int ui2;
unsigned int uresult;

/* Initialize ui1 and ui2 */

uresult = ui1 >> ui2;

Making assumptions about whether a right shift is implemented as an arithmetic (signed) shift or a logical (unsigned) shift can also lead to vulnerabilities. See recommendation INT13-C. Use bitwise operators only on unsigned operands.

Compliant Solution (Right Shift)

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unsigned int ui1;
unsigned int ui2;
unsigned int uresult;

/* Initialize ui1 and ui2 */

if (ui2 >= sizeof(unsigned int) * CHAR_BIT) {
  /* handle error condition */
}
else {
  uresult = ui1 >> ui2;
}

...

GCC has no options to handle shifts by negative amounts or by amounts outside the width of the type predictably or trap on them; they are always treated as undefined. Processors may reduce the shift amount modulo the width of the type. For example, 32-bit shifts are implemented using the following instructions on IA-32:

sa[rl]l   %cl, %eax

The sa[rl]l instructions take a bit mask of the least significant 5 bits from %cl to produce a value in the range [0, 31] and then shift %eax that many bits.

64 bit shifts become
sh[rl]dl  %eax, %edx
sa[rl]l   %cl, %eax

where %eax stores the least significant bits in the double word doubleword to be shifted, and %edx stores the most significant bits.

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Although shifting a negative number of bits or more bits than exist in the operand is undefined behavior in C99C, the risk is generally low because processors frequently reduce the shift amount modulo the width of the type.

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Related Vulnerabilities

Search for vulnerabilities resulting from the violation of this rule on the CERT website.

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CERT C++ Secure Coding Standard: INT34-CPP. Do not shift a negative number of bits or more bits than exist in the operand

ISO/IEC 9899:19992011 Section 6.5.7, "Bitwise shift operators"

ISO/IEC TR 24772 "XYY Wrap-around Errorerror"

ISO/IEC 2003 Section 6.5.7, "Bitwise shift operators"

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A test program for this rule is available at www.securecoding.cert.org.

[Dowd 2006] Chapter 6, "C Language Issues"
[Seacord 2005a] Chapter 5, "Integers"
[Viega 2005] Section 5.2.7, "Integer overflow"

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