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signed long sl1, sl2, result; result = sl1 % sl2; |
Implementation Details
On MSVC++, taking the modulo of INT_MIN by -1 yields the value 0.
On gcc/Linux, taking the modulo of INT_MIN by -1 produces a floating-point exception.
Compliant Solution
This compliant solution tests the modulo operand to guarantee there is no possibility of a divide-by-zero error or an overflow error.
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