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Comment: Edited by sciSpider Java v3.0

Wiki Markup
According to the Java Language Specification \[[JLS 05|AA. Java References#JLS 05]\] section 15.7 "Evaluation Order":

The Java programming language guarantees that the operands of operators appear to be evaluated in a specific evaluation order, namely, from left to right.

Section 15.7.3 "Evaluation Respects Parentheses and Precedence", on the other hand states:

Java programming language implementations must respect the order of evaluation as indicated explicitly by parentheses and implicitly by operator precedence.

These two requirements can be counter intuitive when expressions contain side-effects. This is because, such expressions follow the left to right evaluation order irrespective of operator precedence, associativity rules and indicative parentheses.

Noncompliant Code Example

This noncompliant example shows how side-effects in expressions can lead to unanticipated outcomes. The programmer intends to write access control logic based on different threshold levels. Each user has a rating that must be above the threshold, to be granted appropriate access. As shown, a simple function is used to calculate the rating. The get() method has been used to provide a non-zero factor when the user is authorized and a zero value, when not.

In this case, the programmer expects the rightmost subexpression to evaluate first because of the greater precedence of the operator * than the operator +. The parentheses reinforce this belief. These ideas lead to the incorrect conclusion that the right hand side evaluates to zero whenever the get() method returns zero. The test in the left hand subexpression should ideally reject the unprivileged user as the expected rating value is below the threshold of 10 (expecting number = 0, because of number=get()). Ironically, the program grants access to the unauthorized user. The reason is that evaluation of side-effect infested subexpressions follows the left to right ordering rule and should not be confused with the tenets of operator precedence, associativity and indicative parentheses.

Code Block
bgColor#FFcccc
class BadPrecedence {
  public static void main(String[] args) {
    int number=17;
    int[] threshold = new int[20];
    threshold[0] = 10;
    number = (number > threshold[0]? 0:-2) + ((31 * ++number) * (number=get()));
    // ... 
    if(number == 0)
      System.out.println("Access granted");
    else
      System.out.println("Denied access"); // number = -2
  }
  public static int get() {
    int number=0;
    // assign number to non zero value if authorized else 0
    return number;
  }
}

Compliant Solution

While diligently following the left to right evaluation order, a programmer can expect this compliant solution to evaluate to an expected final outcome depending on the value returned by the get() method.

Code Block
bgColor#ccccff
number = ((31 * ++number) * (number=get())) + (number > threshold[0]? 0:-2);

Although this solution solves the problem, in general, it is advisable to avoid using expressions with more than one side-effect. It is also inadvisable to depend on the left-right ordering for evaluation of side-effects because operands are evaluated in place first, and then subject to laws of operator precedence and associativity.

Risk Assessment

Failing to keep in mind the evaluation order of expressions containing side effects can result in unexpected output.

Rule

Severity

Likelihood

Remediation Cost

Priority

Level

EXP30- J

low

unlikely

medium

P2

L3

Automated Detection

TODO

Related Vulnerabilities

Search for vulnerabilities resulting from the violation of this rule on the CERT website.

References

Wiki Markup
\[[JLS 05|AA. Java References#JLS 05]\] Section 15.7 "Evaluation Order" and 15.7.3 "Evaluation Respects Parentheses and Precedence"


EXP05-J. Be careful about the wrapper class and autoboxing      03. Expressions (EXP)      03. Expressions (EXP)