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Perl provides a simple mechanism for specifying subroutine argument types called prototypes. Prototypes do not affect functions defined using the & character. Furthermore, the perlfunc manpage statesappear to indicate the number and types of arguments that a function takes. For instance, this function appears to require two arguments, the first being a scalar, and the second being a list:

sub function ($@) {
  # ... function body
}

However, prototypes are problematic in many ways. The biggest problem is that prototypes are not enforced by Perl's parser. That is, prototypes do not cause Perl to emit any warnings if a prototyped subroutine is invoked with arguments that violate the prototype.. Perl does not issue any warnings of prototype violations, even if the -w switch is used. 

Prototypes suffer from several other problems, too. They can change function behavior, by forcing scalar context when evaluating arguments that might not be scalars, or by forcing list context when evaluating arguments that might not be lists.  A function's prototype is ignored when that function is invoked with the & character. Finally, according to the perlfunc manpage [Wall 2011]:

Method calls are not influenced by prototypes either, because the function to be called is indeterminate at compile time, since the exact code called depends on inheritance.

Prototypes do not cause Perl to emit any warnings if a subroutine's invocation uses methods that don't match its prototype, not even if the -w switch is used. They also can change function behavior, and consequently should not be usedBecause of these problems, subroutine prototypes must not be used when defining subroutines.

Noncompliant Code Example

This noncompliant code example demonstrates a function with prototypes. The function takes a string and a list and simply prints out the string , along with the list elements.

sub function ($@) {
  my ($item, @list) = @_;

  print "item is $item\n";
  my $size = $#list + 1;
  print "List has $size elements\n";
  foreach my $element (@list) {
    print "list contains $element\n";
  }
}

my @elements = ("Tom", "Dick", "Harry");
function( @elements);

However, this program generates the following counterintuitive output:

item is 3
List has 0 elements

The problem arises from two issues. First, Perl constructs a single argument list from its arguments, and this process includes flattening any arguments that are themselves lists. This is why For this reason, Perl allows function() to be invoked with one list argument , rather than two. Second, the function prototype imposes contexts on the arguments it gets: a single scalar context for the first variable , and a list context from the second variable. These contexts are invoked on the arguments actually provided , rather than on the argument list. In this case, the scalar context is applied to the @elements list, which yields 3, the number of elements in the list. Then the list context is applied to no argument, since only one argument was specified, and it produces an empty list (with 0 elements).

...

sub function {
  my ($item, @list) = @_;

  print "item is $item\n";
  my $size = $#list + 1;
  print "List has $size elements\n";
  foreach my $element (@list) {
    print "list contains $element\n";
  }
}

my @elements = ("Tom", "Dick", "Harry");
function( @elements);

...

Subroutine prototypes do not provide compile-time type safety , and can cause surprising program behavior.

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Bibliography

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