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The conditional operator ?: uses the boolean value of one expression its first operand to decide which of the other two other expressions should will be evaluated. (See §15.25, "Conditional Operator ? :" of the Java Language Specification (JLS) [JLS 2013].)

The general form of a Java conditional expression is operand1 ? operand2 : operand3.

• If the value of the first operand (operand1) is true, then the second operand expression (operand2) is chosen.
• If the value of the first operand is false, then the third operand expression (operand3) is chosen.

The conditional operator is syntactically right-associative. For instance example, a?b:c?d:e?f:g is equivalent to a?b:(c?d:(e?f:g)).

Format:

ConditionalExpression:
ConditionalOrExpression
ConditionalOrExpression ? Expression : ConditionalExpression EXP00-A. Use same type for second and third operands in conditional expressions

• If the value of the first operand is true, then the second operand expression is chosen
• If the value of the first operand is false, then the third operand expression is chosen

The JLS rules for determining the result type of a conditional expression (see following table) are complicated; programmers could be surprised by the type conversions required for expressions they have written.

Result type determination begins from the top of the table; the compiler applies the first matching rule. The Operand 2 and Operand 3 columns refer to operand2 and operand3 (from the previous definition) respectively. In the table, constant int The rules that define the resultant type are given below, where * refers to constant expressions of type int (such as '0' or variables declared as final): final).

For the final table row, S1 and S2 are the types of the second and third operands respectively. T1 is the type that results from applying boxing conversion to S1, and T2 is the type that results from applying boxing conversion to S2. The type of the conditional expression is the result of applying capture conversion to S2. The type of the conditional expression is the result of applying capture conversion to the least upper bound of T1 and T2. See §5.1.7, "Boxing Conversion," §5.1.10, "Capture Conversion," and §15.12.2.7, "Inferring Type Arguments Based on Actual Arguments," of the JLS for additional information [JLS 2013].

Determining the Result Type of a Conditional Expression

Non-Compliant Code Example

The complexity of the rules that determine the result type of a conditional expression can lead to unintended type conversions. Consequently, the second and third operands of each conditional expression should have identical types. This recommendation also applies to boxed primitives.

Noncompliant Code Example

In this noncompliant code example, the programmer expects that both print statements will print the value of alpha as a char:This non-compliant example prints A65 instead of AA. The first print statement prints the value of alpha as type char, that is as A since the third operand is a constant expression of type int (0). The second statement, however, prints 65, the integer equivalent of A. This is because of numeric promotion between the second operand (int) and the third (char) resulting from the use of variable i.

public class exprExpr {
  public static void main(String[] args) {
    char alpha = 'A';
    int i = 0;
    // Other code. Value of i may change 
    boolean trueExp = true; // Some expression that evaluates to true
    System.out.print(true trueExp ? alpha  : 0); // prints A
    System.out.print(falsetrueExp ? ialpha : alphai); // prints 65
  }
}

The first print statement prints A because the compiler applies rule 8 from the result type determination table to determine that the second and third operands of the conditional expression are, or are converted to, type char. However, the second print statement prints 65—the value of alpha as an int. The first matching rule from the table is rule 10. Consequently, the compiler promotes the value of alpha to type int.

Compliant Solution

This compliant solution recommends the use of same uses identical types for the second and third operands . This helps avoid confusion due to clearer semantics.of each conditional expression; the explicit casts specify the type expected by the programmer:

public class exprExpr {
  public static void main(String[] args) {
    char alpha = 'A';
    charint i = 0;
    boolean trueExp = true; //declare as char Expression that evaluates to true
    System.out.print(truetrueExp  ? alpha : :((char) 0)); // Prints A
    // Deliberate narrowing cast of i; possible truncation OK
    System.out.print(falsetrueExp ? ialpha : alpha); ((char) i)); // Prints A
  }
}

Another solution is to declare the offending type as final. As a result, it turns into a constant expression and numeric promotion does not occur.

When the value of i in the second conditional expression falls outside the range that can be represented as a char, the explicit cast will truncate its value. This usage complies with exception NUM12-J-EX0 of NUM12-J. Ensure conversions of numeric types to narrower types do not result in lost or misinterpreted data.

Noncompliant Code Example

This noncompliant code example prints 100 as the size of the HashSet rather than the expected result (some value between 0 and 50):

public class ShortSet

public class expr {
  public static void main(String[] args) {
    charHashSet<Short> alphas = 'A'new HashSet<Short>();
    for int(short i = 0; i < 100; i++) {
      s.add(i);
      // Cast of i-1 is safe because value is always representable
      Short workingVal = (short) (i-1);
      // ... Other code may update workingVal

      s.remove(((i % 2) == 1) ? i-1 : workingVal);
    }
    System.out.print(true  ? alpha  : 0);
    System.out.print(false ? i : alpha.println(s.size());
  }
}

The combination of values of types short and int in the second argument of the conditional expression (the operation i-1) causes the result to be an int, as specified by the integer promotion rules. Consequently, the Short object in the third argument is unboxed into a short, which is then promoted into an int. The result of the conditional expression is then autoboxed into an object of type Integer. Because the HashSet contains only values of type Short, the call to HashSet.remove() has no effect.

Compliant Solution

This compliant solution casts the second operand to type short, then explicitly invokes the Short.valueOf() method to create a Short instance whose value is i-1:

public class ShortSet {
  public static void main(String[] args) {
    HashSet<Short> s = new HashSet<Short>();
    for (short i = 0; i < 100; i++) {
      s.add(i);
      // Cast of i-1 is safe because the resulting value is always representable
      Short workingVal = (short) (i-1);
      // ... Other code may update workingVal

      // Cast of i-1 is safe because the resulting value is always representable
      s.remove(((i % 2) == 1) ? Short.valueOf((short) (i-1)) : workingVal);
    }
    System.out.println(s.size());
  }
}

References

As a result of the cast, the second and third operands of the conditional expression both have type Short, and the remove() call has the expected result.

Writing the conditional expression as ((i % 2) == 1) ? (short) (i-1)) : workingVal also complies with this guideline because both the second and third operands in this form have type short. However, this alternative is less efficient because it forces unboxing of workingVal on each even iteration of the loop and autoboxing of the result of the conditional expression (from short to Short) on every iteration of the loop.

Applicability

When the second and third operands of a conditional expression have different types, they can be subject to unexpected type conversions.

Automated detection of condition expressions whose second and third operands are of different types is straightforward.

Automated Detection

Bibliography

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Image Added Image Added Image AddedJLS 15.25 Conditional Operator ? :
Java Puzzlers, Traps, Pitfalls, Corner Cases 2.8