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Sensitive data stored in reusable resources may be inadvertently leaked to a less privileged user or attacker if not properly cleared. Examples of reusable resources include

• Dynamically allocated memory
• Statically allocated memory
• Automatically allocated (stack) memory
• Memory caches
• Disk
• Disk caches

The manner in which sensitive information can be properly cleared varies depending on the resource type and platform.

Noncompliant Code Example (free())

Dynamic memory managers are not required to clear freed memory and generally do not because of the additional runtime overhead. Furthermore, dynamic memory managers are free to reallocate this same memory. As a result, it is possible to accidentally leak sensitive information if it is not cleared before calling a function that frees dynamic memory. Programmers also cannot rely on memory being cleared during allocation.

To prevent information leakage, sensitive information must be cleared from dynamically allocated buffers before they are freed. Calling free() on a block of dynamic memory marks that memory for deallocation. Once deallocated, the block of memory causes the space to be deallocated; that is, the memory block is made available for future allocation. However, the data stored in the block of memory to be recycled may be preserved. If this memory block contains sensitive information, that information may be unintentionally exposed. Wiki MarkupThis type of defect can lead to information leakage as is stated in Rule: [MEM33-C. Do not assume memory allocation routines initialize memory]. Other attacks, such as _heap inspection_ \[[vulncat|http://vulncat.fortifysoftware.com/2/HI.html] and [samate|http://samate.nist.gov/docs/SAMATE_source_code_analysis_tool_spec_09_15_06.pdf]\] can also occur. To prevent other information leakage and heap inspection it is necessary to clear sensitive information from dynamically allocated buffers before they are freed.

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In this noncompliant example, sensitive information in stored in the buffer dynamically allocated memory referenced by secret is copied to the dynamically allocated buffer, new_secret, which is then processed and eventually marked for deallocation with deallocated by a call to free(). However, the contents of new_secret may remain in heap memory after being marked for deallocation. Furthermore, if this memory is recycled by the heap manager, Because the memory is not cleared, it may be reallocated to another section of the program where the information stored in new_secret may be exposed to another, unintended section of the program, or another program entirelyunintentionally leaked.

...
char *new_secret;
size_t size = strlen(secret);
if (size ==/* Initialize secret to a null-terminated byte string, 
   of less than SIZE_MAX) {
  /* Handle Error */
}

 chars */

size_t size = strlen(secret);
char *new_secret;
new_secret = (char *)malloc(size+1); /* allocate space + NULL Terminator */
if (!new_secret) {
  /* Handle Errorerror */
}
strcpy(new_secret, secret);

/* Process new_secret... */

free(new_secret);
...new_secret = NULL;

Compliant Solution

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To prevent information leakage, dynamic memory containing sensitive information should be sanitized before it is marked for deallocation. Below, this is done by filling the allocated being freed. Sanitization is commonly accomplished by clearing the allocated space (that is, filling the space with '\0' characters).

Code Block
bgColor #ccccff lang c
... char *new_secret; /* Initialize secret to a null-terminated byte string, of less than SIZE_MAX chars */ size_t size = strlen(secret); if (size == SIZE_MAX) { /* Handle Error */ } char *new_secret; /* Use calloc() to zero-out allocated space */ new_secret = malloc (char *)calloc(size+1); /* allocate space + NULL Terminator */, sizeof(char)); if (!new_secret) { /* Handle Errorerror */ } strcpy(new_secret, secret); /* Process new_secret... */ /* Sanitize memory */ memset_s(new_secret, '\0', size); /* sanitize memory */ free(new_secret); new_secret = NULL;

The calloc() function ensures that the newly allocated memory has also been cleared. Because sizeof(char) is guaranteed to be 1, this solution does not need to check for a numeric overflow as a result of using calloc().

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(See MEM07-C. Ensure that the arguments to calloc(), when multiplied, do not wrap.)

See MSC06-C. Beware of compiler optimizations for a definition and discussion of using the memset_s() function.

Noncompliant Code Example (realloc())

Reallocating memory using realloc() can have the same problem as freeing memory. The realloc() function deallocates the old object and returns a pointer to a new object. Using

Non-Compliant Code Example 2

Using realloc() to resize dynamic memory may inadvertently expose sensitive information, or it may allow heap inspection, as described in Fortify Taxonomy: Software Security Errors [Fortify 2006] and NIST's Source Code Analysis Tool Functional Specification [Black 2007].

In this example, when realloc()is called, it may allocate a new, larger block of memoryobject, copy the contents , of buffer secret to this new blockobject, free() the original blockobject, and assign the newly allocated block object to buffersecret. However, the contents of the original block object may remain in heap memory after being marked for deallocation.

char *secret;

/* Initialize secret */

size_t secret_size = strlen(secret);
/* ...
buffer */
if (secret_size > SIZE_MAX/2) {
   /* Handle error condition */
}
else {
secret = (char *)realloc(buffersecret,new secret_size * 2);
}

The secret_size is tested to ensure that the integer multiplication (secret_size * 2) does not result in an integer overflow. (See INT30-C.

...

Ensure that unsigned integer operations do not wrap.)

Compliant Solution

A compliant program cannot rely on realloc() because it is not possible to clear the memory before the call. Instead, a custom function must be used that operates similarly to realloc() but sanitizes sensitive information as heap-based buffers are resized. Again, sanitization is done by overwriting the space to be deallocated with '\0' characters.

char *secret;

/* Initialize secret */

size_t secret_size = strlen(secret);
char *temp_buff;
/* ... */
if (secret_size > SIZE_MAX/2) {
   /* Handle error condition */
}
/* calloc() initializes memory to zero */
temp_buff = (char *)calloc(secret_size * 2, sizeof(char));
if (temp_buff == NULL) {
 /* Handle error */
}

memcpy(temp_buff, secret, secret_size);

/* Sanitize the buffer */
memset((volatile char *)secret, '\0', secret_size);

free(secret);
secret = temp_buff; /* Install the resized buffer */
temp_buff = NULL;

The calloc() function ensures that the newly allocated memory is also cleared. Because sizeof(char) is guaranteed to be 1, this solution does not need to check for a numeric overflow as a result of using calloc(). (See MEM07-C. Ensure that the arguments to calloc(), when multiplied, do not wrap.)

Risk Assessment

In practice, this type of security flaw can expose sensitive information to unintended parties. The Sun tarball vulnerability discussed in Secure Coding Principles & Practices: Designing and Implementing Secure Applications [Graf 2003] and Sun Security Bulletin #00122 [Sun 1993] shows a violation of this recommendation, leading to sensitive data being leaked. Attackers may also be able to leverage this defect to retrieve sensitive information using techniques such as heap inspection.

Compliant Solution 2

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Risk Assessment

Failure to clear dynamic memory can result in leaked information.

Refernces

Automated Detection

Related Vulnerabilities

Search for vulnerabilities resulting from the violation of this rule on the CERT website.

Related Guidelines

Bibliography

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Image Added Image Added Image Addedhttp://vulncat.fortifysoftware.com/2/HI.html
http://samate.nist.gov/docs/SAMATE_source_code_analysis_tool_spec_09_15_06.pdf
MEM33-C. Do not assume memory allocation routines initialize memory