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Function declarators must be declared with the appropriate type information, including a return type and parameter list. If type information is not properly specified in a function declarator, the compiler cannot properly check function type information. When using standard library calls, the easiest (and preferred) way to obtain function declarators with appropriate type information is to include the appropriate header file.

Attempting to compile a program with a function declarator that does not include the appropriate type information typically generates a warning but does not prevent program compilation. These warnings should be resolved. (See MSC00-C. Compile cleanly at high warning levels.)

Noncompliant Code Example (Non-Prototype-Format Declarators)

This noncompliant code example uses the identifier-list form for parameter declarations:

int max(a, b)
int a, b;
{
  return a > b ? a : b;
}

Subclause 6.11.7 of the C Standard [ISO/IEC 9899:2011] states that "the use of function definitions with separate parameter identifier and declaration lists (not prototype-format parameter type and identifier declarators) is an obsolescent feature."

Compliant Solution (Non-Prototype-Format Declarators)

In this compliant solution, int is the type specifier, max(int a, int b) is the function declarator, and the block within the curly braces is the function body:

int max(int a, int b) {
  return a > b ? a : b;
}

Noncompliant Code Example (Function Prototypes)

Declaring a function without any prototype forces the compiler to assume that the correct number and type of parameters have been supplied to a function. This practice can result in unintended and undefined behavior.

In this noncompliant code

Failure to specify function prototypes results in a function being implicitly defined. Without a function prototype, the compiler will assume the the correct number and type of parameters have been supplied to a function. This can result in undefined, and perhaps unintended behavior. Given this, functions should always be declared with the appropriate function prototype.

C99 eliminated implicit function declarations from the C language \[[ISO/IEC9899-1999|AA. C References#ISO/IEC 9899-1999]\]. However, many compilers allow compilation of programs containing implicitly defined functions, although they may issue a warning message. These warnings should be resolved \[[MSC00-A|MSC00-A. Compile cleanly at high warning levels]\], but do not prevent program compilation.

Non-Compliant Code Example 1

In this example, the definition of func() in file_a.c expects three parameters but is supplied only two:

/* file_a.c source file */
int func(int one, int two, int three){
  printf("%d %d %d", one, two, three);
  return 1;
}

However, because there is no prototype for func() in file_b.c, the compiler assumes that the correct number of arguments has been supplied , and uses the next value on the program stack as the missing third argument.:

/* file_b.c source file */
func
function(1, 2);

C99 eliminated implicit function declarations from the C language. However, many compilers still allow the compilation of programs containing implicitly declared functions, although they may issue a warning message. These warnings should be resolved. (See MSC00-C. Compile cleanly at high warning levels.)

Compliant Solution (Function Prototypes)

This compliant solution correctly includes the function prototype for func() in the compilation unit in which it is invoked, and the function invocation has been corrected to pass the right number of arguments:

/* file_b.c source file */
int func(int one, int two, int three){
  printf("%d %d %d", one, two, three);
  return 1;
}

Compliant Solution 1

To correct this example, the appropriate function prototype for func() should be specified.

int function(int, int, int);
...

function(1,2);
...
int func(int one, int two, int three){
  printf("%d %d %d", one, two, three);
  return 1;
}

Non-Compliant Code Example 2

The following example is based on rule \[[MEM02-A|MEM02-A. Do not cast the return value from malloc()]\]. The header file {{stdlib.h}} contains the function prototype for {{malloc()}}. Failing to include {{stdlib.h}} causes {{malloc()}} to be implicitly defined.

char *p = malloc(10);

Compliant Solution 2

including stdlib.h ensures the function prototype for malloc() is declared.

#include <stdlib.h>
...
char *p = malloc(10);

Risk Assessment

Failure to specify function prototypes can result in undefined, and perhaps unintended program behavior.

;

func(1, 2, 3);

Noncompliant Code Example (Function Pointers)

If a function pointer refers to an incompatible function, invoking that function via the pointer may corrupt the process stack. As a result, unexpected data may be accessed by the called function.

In this noncompliant code example, the function pointer fn_ptr refers to the function add(), which accepts three integer arguments. However, fn_ptr is specified to accept two integer arguments. Setting fn_ptr to refer to add() results in unexpected program behavior. This example also violates EXP37-C. Call functions with the correct number and type of arguments:

int add(int x, int y, int z) {
  return x + y + z;
}

int main(int argc, char *argv[]) {
  int (*fn_ptr) (int, int);
  int res;
  fn_ptr = add;
  res = fn_ptr(2, 3);  /* Incorrect */
  /* ... */
  return 0;
}

Compliant Solution (Function Pointers)

To correct this example, the declaration of fn_ptr is changed to accept three arguments:

int add(int x, int y, int z) {
  return x + y + z;
}

int main(int argc, char *argv[]) {
  int (*fn_ptr) (int, int, int) ;
  int res;
  fn_ptr = add;
  res = fn_ptr(2, 3, 4);
  /* ... */
  return 0;
}

Risk Assessment

Failing to include type information for function declarators can result in unexpected or unintended program behavior.

Automated Detection

Related Vulnerabilities

Search for Examples of vulnerabilities resulting from the violation of this rule can be found on the CERT website.

References

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Related Guidelines

Bibliography

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