EXP00-J. Use the same type for the second and third operands in conditional expressions

The conditional operator ?: uses the boolean value of one expression to decide which of the other two expressions should be evaluated [[JLS 05]].

The conditional operator is syntactically right-associative. For instance a?b:c?d:e?f:g is equivalent to a?b:(c?d:(e?f:g)).

Format:

ConditionalExpression:
ConditionalOrExpression
ConditionalOrExpression ? Expression : ConditionalExpression

If the value of the first operand is true, then the second operand expression is chosen
If the value of the first operand is false, then the third operand expression is chosen

The rules that define the resultant type are given in the following table, where the first match, starting from the top, is used. In the table, * refers to constant expressions of type int (such as '0' or variables declared final):

Operand 2	Operand 3	Resultant type
type T	type T	type T
`boolean`	`Boolean`	`boolean`
`Boolean`	`boolean`	`boolean`
`null`	`reference`	`reference`
`reference`	`null`	`reference`
`byte` or `Byte`	`short` or `Short`	`short`
`short` or `Short`	`byte` or `Byte`	`short`
`byte`, `short`, `char`	`const int*`	`byte`, `short`, `char` if value of `int` is representable
`const int*`	`byte`,`short`,`char`	`byte`, `short`, `char` if value of `int` is representable
`Byte`	`const int*`	`byte` if `int` is representable as `byte`
`const int*`	`Byte`	`byte` if `int` is representable as `byte`
`Short`	`const int*`	`short` if `int` is representable as `short`
`const int*`	`Short`	`short` if `int` is representable as `short`
`Character`	`const int*`	`char` if `int` is representable as `char`
`const int*`	`Character`	`char` if `int` is representable as `char`
other numeric	other numeric	promoted type of the 2nd and 3rd operands
T1 = boxing conversion (S1)	T2 = boxing conversion(S2)	apply capture conversion to lub(T1,T2)

Noncompliant Code Example

This noncompliant example prints A65 instead of AA. The first print statement prints the value of alpha as A which is of the char type. The third operand '0', is a constant expression of type int and does not cause any numeric promotion. The second statement, however, prints 65, the integer equivalent of A. This is because of numeric promotion of the third operand alpha to an int which happens as a result of variable i being an int.

public class Expr {
  public static void main(String[] args) {
    char alpha = 'A';
    int i = 0;
    System.out.print(true  ? alpha  : 0);
    System.out.print(false ? i : alpha);
  }
}

Compliant Solution

This compliant solution recommends the use of the same types for the second and third operands of the conditional expressions. The clearer semantics help avoid confusion.

public class Expr {
  public static void main(String[] args) {
    char alpha = 'A';
    char i = 0;        //declare as char
    System.out.print(true  ? alpha  : 0);
    System.out.print(false ? i : alpha);
  }
}

Exceptions

EXP00: It is permissible to use operands of different types when the offending type is declred final. Consequently, it turns into a constant expression and numeric promotion does not occur.

public class Expr {
  public static void main(String[] args) {
    char alpha = 'A';
    final int i = 0;
    System.out.print(true  ? alpha  : 0);
    System.out.print(false ? i : alpha);
  }
}

Risk Assessment

If the types of the second and third operands in a conditional expression are not the same then the result of the conditional expression may be unexpected.

Rule	Severity	Likelihood	Remediation Cost	Priority	Level
EXP00- J	low	unlikely	medium	P2	L3

Automated Detection

TODO

Related Vulnerabilities

Search for vulnerabilities resulting from the violation of this rule on the CERT website.

References

[[JLS 05]] Section 15.25, Conditional Operator ? :
[[Bloch 05]] Puzzle 8: Dos Equis

03. Expressions (EXP) 03. Expressions (EXP) EXP01-J. Ensure a null pointer is not dereferenced

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