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If an environment variable might have changed during program execution, get a fresh copy using getenv(). If you rely on your old variable, you could be left with incorrect data or a dangling pointer.

Non-Compliant Coding Example

After a call to setenv(), environment pointers to the old value and copies of the old value will be incorrect.

char *temp;
char *copy;

if ((temp = getenv("TEST_ENV")) != NULL) {
  copy = malloc(strlen(temp) + 1);
  if (copy != NULL) {
    strcpy(copy, temp);
  }
  else {
    /* handle error condition */
  }
}
/* ...program code... */
setenv("TEST_ENV", var, 1);
/* ...program code... */


printf("TEST_ENV: %s\n", temp);
printf("TEST_ENV: %s\n", copy);

Neither of the print statements will be correct.

Compliant Solution

You should always fetch fresh copies of environment variables, especially if you know that a value has changed.

char *temp;
char *copy;

if ((temp = getenv("TEST_ENV")) != NULL) {
   copy = malloc(strlen(temp) + 1);
   if (copy != NULL) {     
      strcpy(copy, temp);   
   }
   else {
      /* handle error condition */
   }
}
/* ...program code... */
setenv("TEST_ENV", var, 1);
/* ...program code... */

if ((temp = getenv("TEST_ENV")) != NULL) {
   copy = malloc(strlen(temp) + 1);
   if (copy != NULL) {    
      strcpy(copy, temp);  
   }
   else
   {     
      /* handle error condition */   
   }
}

printf("TEST_ENV: %s\n", temp);
printf("TEST_ENV: %s\n", copy);

This will provide us with the current value of the environment variable.

Risk Assessment

The program would not be using current environment values, causing unexpected results.

Rule

Severity

Likelihood

Remediation Cost

Priority

Level

ENV31-C

1 (low)

1 (low)

3 (low)

P3

L3

References

[[ISO/IEC 9899-1999:TC2]] Section 7.20.4, "Communication with the environment"

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