MEM38-C. Use Flexible Array Members for dynamically sized structures

Flexible array members is a special type of struct, where the last element of a structure with more than one named member is has an incomplete array type; that is, the size of the array is not specified within the struct.

This technique has widely been known as the "struct hack." However, the classical method of the "struct hack" results in undefined behavior, although it may work most of the time.

Non-Compliant Code Example

The following is the old, incorrect "struct hack" which results in undefined behavior.

struct hack {
	int num;
	char my_char;
	int data[1];
};

...
/* Space is allocated for the struct */
struct hack * hackP = malloc( sizeof(struct hack) + sizeof(int) * (ARRAY_SIZE-1) );
if(!hackP) {
	/* handle malloc failure */
}
hackP -> num = SOME_NUMBER;
hackP -> my_char = SOME_CHAR;

/* Access data[] as if it had been allocated as data[ARRAY_SIZE] */
for(i=0; i<ARRAY_SIZE; i++)
	hackP -> data[i] = i;

This is, strictly speaking, undefined behavior when accessing hackP->data[i] for i>0, since that goes beyond the bounds of the array.

Compliant Solution

The solution is part of the C99 standard, the flexible array member.

struct hack {
	int num;
	char my_char;
	int data[];
};

...
/* Space is allocated for the struct */
struct hack * hackP = malloc( sizeof(struct hack) + sizeof(int) * ARRAY_SIZE );
if(!hackP) {
	/* handle malloc failure */
}
hackP -> num = SOME_NUMBER;
hackP -> my_char = SOME_CHAR;

/* Access data[] as if array had been allocated as data[ARRAY_SIZE] */
for(i=0; i<ARRAY_SIZE; i++)
	hackP -> data[i] = i;

No actual array space is allocated within the struct object. By mallocating space for the struct, the space computation is done at runtime, and allows the programmer to dynamically allocate space for an array within a struct.

However, some restrictions do apply. The incomplete array type MUST be the last element within the struct. You also cannot have an array of objects if the object has flexible array members. Nor can such object be used as a member in the middle of another struct.

Risk Assessment

Although the old "stack hack" method results in undefined behavior, it will work most of the time.

References

[[McCluskey 01]] ;login:, July 2001, Volume 26, Number 4
[[ISO/IEC 9899-1999]] Section 6.7.2.1, "Structure and union specifiers"